我正在使用用户Keevas的例子,但问了一个不同的问题......
select Master_Code, SUM(Jan), SUM(Feb), SUM(Mar)
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code ORDER BY Master_Code ASC
类似的东西:
Master_Code sum(Jan) Sum(Feb) sum(Mar) Total
1 4 5 4 13
2 5 5 5 15
如何获得总价值列?谢谢!
答案 0 :(得分:0)
select Master_Code,
SUM(Jan),
SUM(Feb),
SUM(Mar),
SUM(Jan+Feb+Mar) as Total
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code
ORDER BY Master_Code ASC
答案 1 :(得分:0)
这应该有效:
select Master_Code
, SUM(Jan)
, SUM(Feb)
, SUM(Mar)
, (SUM(Jan + Feb + Mar)) As Total
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code
ORDER BY Master_Code ASC
答案 2 :(得分:0)
只需使用加号添加它们。
SELECT Master_Code, SUM(Jan), SUM(Feb), SUM(Mar), SUM(Jan) + SUM(Feb) + SUM(Mar) FROM...