我需要得到最后一行结果集的所有列值的总和 这是我的SQL查询。
select Master_Code, SUM(Jan), SUM(Feb), SUM(Mar)
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code ORDER BY Master_Code ASC
类似的东西:
Master_Code Jan Feb Mar
1 4 5 6
2 5 5 5
Total 9 10 11
答案 0 :(得分:16)
建立联合,重复相同的查询,但没有分组:
select Title, Jan, Feb, Mar
from (
select Master_Code as Title, SUM(Jan) as Jan, SUM(Feb) as Feb, SUM(Mar) as Mar
from dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code ORDER BY Master_Code ASC
) x
union all
select 'Total', SUM(Jan) as Jan, SUM(Feb) as Feb, SUM(Mar) as Mar
from dbo.foobar
WHERE Participating_City = 'foofoo'
答案 1 :(得分:11)
假设没有空的master_code行。
SELECT ISNULL(Master_code, 'Total') AS Master_Code,
Jan,
Feb,
Mar
FROM (
SELECT Master_code,
SUM(Jan) AS Jan,
SUM(Feb) AS Feb,
SUM(Mar) AS Mar
FROM foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_code WITH ROLLUP
) AS DT
答案 2 :(得分:3)
您也可以使用Coalesce和With Rollup。
SELECT COALESCE(Master_Code, 'TOTAL') AS MASTER_CODE, SUM(Jan), SUM(Feb), SUM(Mar)
FROM dbo.foobar
WHERE Participating_City = 'foofoo'
GROUP BY Master_Code WITH ROLLUP
ORDER BY Master_Code DESC