Question

我有一张名为 patientinfo 的表格，如下所示：

和名为 tblpayment 的表b如下：

现在，我想要的是从表A 获取PatientId和PatientName今天加入表B 的付款日期和SUM（paymentTotal），SUM（paymentPaid）但最后一行付款保留。

简单来说，我希望所有今天的患者都支付总金额和支付金额，但是最后一行支付费用。

从图形上看，我想要的应该是：

patientId   paymentTotal   paymentPaid   paymentRemaining
    252         123500        118500          5000
    253         60000         55000           5000
    254         17500         17500            0
    258         5800            0             5800

注意：记录应为当前日期。

任何帮助？

到目前为止我做了什么：

   SELECT a.patientId , a.patientName, b.paymentTotal , b.paymentPaid , b.paymentRemaining FROM
      patientinfo a
      inner join
      (
      SELECT  patienId , SUM(paymentTotal) as paymentTotal ,SUM(paymentPaid) as paymentPaid,
      MAX(paymentRemaining) as paymentRemaining
      FROM tblpayment WHERE paymentDate LIKE '%$date%' GROUP BY patienId
      )b
      on a.patientId  = b.patienId

一切都很好，但是这个查询中的错误是它给了我第一个值paymentRemaining的值。然而，我想要付款的最后一个值，它给我MAX值。我该怎么用Max替换这个？

修改

我的问题有点不对劲。我不希望MAX支付剩余，但最后一行支付剩余的患者ID。

Answer 1

MIN只需要MAX而不是LEFT JOIN：

 SELECT DISTINCT
   t.patientId, 
   b.paymentTotal , 
   b.paymentPaid , b.paymentRemaining 
FROM tblpayment AS t 
LEFT JOIN patientinfo a ON t.patientId = a.patientId
LEFT join
(
   SELECT  patientId , SUM(paymentTotal) as paymentTotal,
     SUM(paymentPaid) as paymentPaid,
     MIN(paymentRemaining) as paymentRemaining
   FROM tblpayment 
  GROUP BY patientId
) b on t.patientId  = b.patientId

demo

这将为您提供您想要的内容：

| patientId | paymentTotal | paymentPaid | paymentRemaining |
|-----------|--------------|-------------|------------------|
|       252 |       123500 |      118500 |             5000 |
|       253 |        60000 |       55000 |             5000 |
|       254 |        17500 |       17500 |                0 |
|       258 |         5800 |           0 |             5800 |

<强>更新

如果你想要最后一行，那么它将是每个patientid的最新日期。然后试试这个：

SELECT DISTINCT
   t.patientId, 
   b.paymentTotal , 
   b.paymentPaid , 
   t.paymentRemaining 
FROM
(
   a.patientId, paymentRemaining, paymentDate
   FROM tblpayment AS t 
   LEFT JOIN patientinfo a ON t.patientId = a.patientId
) AS t
INNER join
(
   SELECT  patientId , SUM(paymentTotal) as paymentTotal,
     SUM(paymentPaid) as paymentPaid
   FROM tblpayment 
  GROUP BY patientId
) b on t.patientId  = b.patientId
INNER JOIN
(
   SELECT patientId, MAX(paymentDate) AS LatestDate
   FROM tblpayment 
   GROUP BY patientId
) AS s ON s.patientId = t.patientId AND t.paymentDate = s.LatestDate

使用Id获取当前日期一列的两列和最后一行的总和 - MYSQL

1 个答案: