Question

使用与此问题相关的问题Get Last Row of Different id then display data that is greater than zero

我想加入另一张表

这是我的table2

+----+--------+
| id | name   | 
+----+--------+
| 1  | Taylor |
| 2  | Zac    |
| 3  | Scott  |
| 4  | Emma   |
+----+--------+

如果我使用此代码......

SELECT DISTINCT t1.id, t1.amount, t2.name FROM table1 t1, table2 t2 WHERE t1.amount = (SELECT MIN(t1.amount) FROM table1 WHERE id= t1.id) AND t1.[t1.amount]>0 AND t1.[id]=t2.[id];

......然后这些结果显示......

+----+--------+-------+
| id | amount | name  |
+----+--------+-------+
| 2  | 100    | Zac   |
+----+--------+-------+

仅显示1个数据

我想要的是表格中的数据

+----+--------+-------+
| id | amount | name  |
+----+--------+-------+
| 2  | 100    | Zac   |
| 4  | 200    | Emma  |
+----+--------+-------+

Answer 1

相信你正在寻找第一张表的子查询，请尝试以下方法：

SELECT DISTINCT t1.id, t1.amount, t2.name 
FROM (SELECT DISTINCT id, amount FROM table t 
WHERE amount = (SELECT MIN(amount) FROM table WHERE id= t.id)
and amount>0) t1, table2 t2 
WHERE t1.[id]=t2.[id];

不确定为什么您当前的查询不起作用，但希望这有帮助！

Answer 2

SELECT DISTINCT t.id,t2.name,t.amount 
FROM table t
INNER JOIN table2 t2 ON t.id=t2.id 
WHERE amount = (SELECT MIN(amount) FROM table WHERE id= t.id)
and amount>0;

Answer 3

请尝试以下方法......

SELECT table2.id AS id,
       minAmount AS amount,
       name
FROM ( SELECT id,
              MIN( amount ) AS minAmount
       FROM table1
       GROUP BY id
       HAVING MIN( amount ) > 0
     ) AS table1Refiner
INNER JOIN table2 ON table1Refiner.id = table2.id;

此声明的工作原理是根据您的第一个问题获取结果，并根据table2的共享值将其加入id，有效地将相应的name附加到每个id }和amount。然后选择并输出字段。

如果您有任何问题或意见，请随时发表评论。

获取最后一行或最小数据然后连接两个表

3 个答案: