我试图从一个表中选择一个品牌列表,从另一个表中选择品牌描述。一个品牌可以有多个描述。我想拥有的是这样的:
Brand1
-brand1 description 1
-brand1 description 2
...etc
我现在拥有的:
Brand1
-brand1 description1
-brand1 description2
Brand1
-brand1 description1
-brand1 description2
模特功能:
function get_brand_desc() {
$query = "SELECT a.id AS aid, a.brand, b.* FROM brands a
LEFT JOIN brand_desc b ON a.id = b.brand_id";
$q = $this->db->query($query);
if($q->num_rows() > 0)
{
foreach($q->result() as $descs)
{
$data[] = $descs;
}
return $data;
}else{
return false;
}
}
控制器:
$admin_data['descs'] = $this->admin_model->get_brand_desc();
查看:
<?php
echo '<ul>';
foreach($descs as $desc) {
echo '<li>';
echo '<p>'.$desc->brand.'</p>';
echo '<p>'.$desc->description.'</p>';
echo '</li>';
}
echo '</ul>';
?>
答案 0 :(得分:4)
按品牌订购您的查询,将所有brand_desc
行组合在一起。因此,您的查询如下所示:
SELECT
a.id AS aid,
a.brand,
b.*
FROM
brands a
LEFT JOIN
brand_desc b ON
a.id = b.brand_id
ORDER BY
a.brand
现在,当您循环商品时,您将有几行重复品牌名称 - 每个品牌描述。不要将此查询视为为您提供品牌列表,而应将其视为为您提供所有品牌描述的列表。因此,当您输出时,您必须定义分组。
echo '<ul>';
$currentBrand = false;
foreach($descs as $desc) {
if ($currentBrand != $desc->brand) {
if ($currentBrand !== false)
echo '</li>'; // if there was a brand LI open, close it
echo '<li>'; // open a new LI for this new brand
echo '<p>'.$desc->brand.'</p>';
$currentBrand = $desc->brand;
}
echo '<p>'.$desc->description.'</p>';
}
echo '</li>'; // closing out the brand that is left hanging open at the end
echo '</ul>';
答案 1 :(得分:0)
您永远不会在foreach循环中更新您的品牌信息。你应该构建一个数组数组:
$ data ['brand1'] =&gt; brand1的所有描述的数组 $ data ['brand2'] =&gt; brand2的所有描述的数组 [...]
答案 2 :(得分:-1)
像这样建立你的查询:
$query = "SELECT DISTINCT a.id AS aid, a.brand, b.descriptionColumn FROM brands a
LEFT JOIN brand_desc b ON a.id = b.brand_id";