Question

我有两个桌子

 Col1  COl2  COl3  Col4
    1          3     
    3          5      
    4          6

第二张表也相同

Col11  COl21  COl31  Col41
  1            3     
  3            5      
  4            6

我想逐行并产生如下输出

Col11  Col21       COl31  Col41
 1     Col1/Col11    3    Col3/Col31
 3     Col1/Col11    5     ..
 4     Col1/Col11    6     ....

我可以进行内部联接并找到匹配的记录，但是在这种情况下，我没有任何要匹配的列，我只想逐行进行计算。.有人可以告诉我如何实现这个。

Answer 1

尝试

DECLARE @Tab1 AS TABLE (Col1 INT,COl2 INT,  COl3 INT,  Col4 INT)
INSERT INTO @TAb1
SELECT 1,NULL,3,NULL UNION ALL     
SELECT 3,NULL,5,NULL UNION ALL      
SELECT 4,NULL,6,NULL 

DECLARE @Tab2 AS TABLE (Col11 INT,COl21 INT,  COl31 INT,  Col41 INT)
INSERT INTO @TAb2
SELECT 1,NULL,3,NULL UNION ALL     
SELECT 3,NULL,5,NULL UNION ALL      
SELECT 4,NULL,6,NULL 

;WITH CTE
AS
(
SELECT Col11,'Col11'AS COl21  ,COl31 ,'COl31' AS Col41 
FROM @Tab2   
UNION ALL
SELECT Col1,'Col1' ,COl3,'COl3' 
FROM @Tab1
)
    SELECT  
    Col11,
    STUFF((SELECT DISTINCT '/'+COl21 FROM CTE i WHERE i.Col11=o.Col11
        FOR XML PATH ('')),1,1,'') As COl21,
    COl31,
    STUFF((SELECT DISTINCT '/'+Col41 FROM CTE i WHERE i.COl31=o.COl31
        FOR XML PATH ('')),1,1,'') As Col41 
FROM CTE o
GROUP BY Col11,COl31

结果

Col11    COl21      COl31     Col41
----------------------------------------
1       Col1/Col11    3     COl3/COl31
3       Col1/Col11    5     COl3/COl31
4       Col1/Col11    6     COl3/COl31

逐行连接两个表

1 个答案: