我正在使用quicksort 3路分区,但是当矢量大小大于10000时,它变得太慢了。 我究竟做错了什么?请指导我!任何帮助将不胜感激 答案应该在不到2.2秒的时间内计算出来。
#include <iostream>
#include <vector>
#include <cstdlib>
#include <algorithm>
using std::vector;
using std::swap;
void print(vector<int> v)
{
for(int i = 0; i < v.size(); i++) std::cout << v[i] << " ";
std::cout << std::endl;
}
void partition2(vector<int> &a, int l, int r, int &i, int &j) {
int k;
int middle=(l+r)/2;
/*Selecting pivot as median of low, high and middle*/
if(((a[l]<=a[middle]) && (a[middle]<=a[r])) || ((a[r]<=a[middle]) && (a[middle]<=a[l])))
k=middle;
else if(((a[middle]<=a[l]) && (a[l]<=a[r])) || ((a[r]<=a[l]) && (a[l]<=a[middle])))
k=l;
else if(((a[middle]<=a[r]) && (a[r]<=a[l])) || ((a[l]<=a[r]) && (a[r]<=a[middle])))
k=r;
swap(a[l], a[k]);
//print(a);
int low_value = a[l];
int index_low = l;
int index_high = l;
int counter=l;
for (int i = l + 1; i <= r; i++) {
if (a[i] < low_value) {
swap(a[i], a[index_low]);
counter++;
low_value=a[l];
}
else if(a[i]==low_value)
{
index_high++;
swap(a[i], a[index_high]);
}
//print(a);
}
i=counter;
j=index_high;
//swap(a[l], a[j]);
//return j;
}
void randomized_quick_sort(vector<int> &a, int l, int r) {
if (l >= r) {
return;
}
int i,j;
partition2(a, l, r, i, j);
randomized_quick_sort(a, l, i-1);
randomized_quick_sort(a, j+1, r);
}
int main() {
int n;
std::cin >> n;
//while(1){
//n=100+rand()%99999;
//std::cout<<n<<std::endl;
vector<int> a(n);
for (size_t i = 0; i < a.size(); ++i) {
std::cin >> a[i];
//a[i]=1+rand()%99999999;
}
randomized_quick_sort(a, 0, a.size() - 1);
for (size_t i = 0; i < a.size(); ++i) {
std::cout << a[i] << ' ';
}
//std::cout<<"Pass\n";
//}
return 0;
}
答案 0 :(得分:0)
乍一看一切都是正确的。但是,可能只有太多的比较操作。试试这个选项 - 它平均在我的电脑上运行1.6秒。
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <ctime>
#include <random>
#include <chrono>
#include <iomanip>
using namespace std;
using namespace std::chrono;
//======= quick_sort =======//
template<typename T>
int partition(vector<T>& numbers, const int& left, const int& right)
{
swap(numbers[left], numbers[left + (right - left) / 2]);
T mid = numbers[left];
int i(left + 1), j(right);
while (i <= j)
{
while ( i <= j && numbers[i] <= mid ) i++;
while ( i <= j && numbers[j] > mid ) j--;
if ( i < j ) swap(numbers[i], numbers[j]);
}
swap(numbers[i - 1], numbers[left]);
return i - 1;
}
template<typename T>
void quick_sort_rec(vector<T>& numbers, const int& left, const int& right)
{
if (left >= right) return;
int p = partition(numbers, left, right);
quick_sort_rec(numbers, left , p - 1);
quick_sort_rec(numbers, p + 1 , right);
}
//=========================//
template<typename T>
T random_T(long min, long max)
{
return (T)min + static_cast<T>(rand()) / (static_cast<T>(RAND_MAX / ((T)(max - min))));
}
template<typename T>
float time_func(void (*f)(vector<T>&, const int&, const int&), vector<T>& a)
{
high_resolution_clock::time_point t1 = high_resolution_clock::now();
f(a, 0, a.size() - 1);
high_resolution_clock::time_point t2 = high_resolution_clock::now();
return 1000.0 * (duration_cast<microseconds>(t2 - t1).count()) / (float)(CLOCKS_PER_SEC); /// CLOCKS_PER_SEC;
}
int main()
{
srand((unsigned)(777));
vector<int> a;
for (int i = 0; i < 10000; i++)
{
a.push_back(random_T<int>(0, 1000));
}
cout << setprecision(10) << "quick sort rec = " << time_func(quick_sort_rec, a) << endl;
return 0;
}
答案 1 :(得分:0)
我运行以下代码来测试partition2
int main(){
vector<int> a = {2, 1, 1, 9, 5, 3, 4, 2, 7};
int i, j;
partition2(a, 0, a.size() - 1, i, j);
for (auto i : a)
cout << i << ' ';
cout << '\n';
return 0;
}
结果是
1 1 5 9 2 3 4 2 7
如果partition2选择low,high和middle的中位数作为pivot,那么pivot应该是5,结果应该是
2 1 1 3 4 2 5 9 7
然后我检查代码
if (a[i] < low_value) {
swap(a[i], a[index_low]);
counter++;
low_value=a[l];
}
else if(a[i]==low_value)
{
index_high++;
swap(a[i], a[index_high]);
}
似乎代码试图找到数组的最小值,然后将它们移动到数组的开头。它似乎正在做选择排序而不是快速排序。它解释了当输入大小很大时为什么它很慢。