Question

这是我的T-SQL代码：

SELECT  H.ORDER_DATE 'Order Date',
        SUM(D.WORK_QTY) 'Work Qty',
        SUM(TD. TRAN_QTY) 'Transaction Qty',
        IM.PUMJ_CD

FROM [dbo].[ORDER_HEADER] H

    LEFT JOIN ORDER_DETAIL D ON D.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_HEADER T ON T.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_DETAIL TD ON TD.TRAN_ID = T.TRAN_ID
    LEFT JOIN TRAN_TYPE TT ON TT.TRAN_TYPE_ID = TD.TRAN_TYPE_ID 
    LEFT JOIN ITM_MST IM ON IM.ITM_NM = D.ITEM_NAME

WHERE   TD.TRAN_TYPE_ID = '231' 
        AND PUMJ_CD IN ('BF','BR','SHFT','BJ','TJ')
        AND H.ORDER_DATE BETWEEN '20170403' AND '20170407'

GROUP BY    IM.PUMJ_CD,
            H.ORDER_DATE

ORDER BY    H.ORDER_DATE

并返回记录集：

Order Date | Work Qty | Transaction Qty | PUMJ_CD
-------------------------------------------------
20170403   | 10       | 7               | BF
20170403   | 24       | 12              | BR
20170403   | 16       | 14              | TJ
20170404   | 15       | 10              | BF

是否可以对记录集中的行进行求和，其中：＆＃39;订单日期＆＃39;是一样的，而且 PUMJ_CD IN（＆＃39; BF＆＃39;，＆＃39; BR＆＃39;）并将结果记录集看起来像：

Order Date | Work Qty | Transaction Qty | PUMJ_CD
-------------------------------------------------
20170403   | 34       | 19              | TOTAL
20170403   | 16       | 14              | TJ
20170404   | 15       | 10              | BF

我一直试图在一个查询中找到一种方法来做到这一点，但由于我的知识有限，我还没有成功。我尝试过在线查看，但我发现很难用google中的问题描述我需要的东西。如果有人能帮忙或指出我正确的方向，我们将非常感激。

Answer 1

是。您可以使用CASE进行汇总，也可以使用SELECT：

SELECT  H.ORDER_DATE as [Order Date],
        SUM(D.WORK_QTY) as [Work Qty],
        SUM(TD. TRAN_QTY) as [Transaction Qty],
        (CASE WHEN IM.PUMJ_CD IN ('BF','BR') THEN 'TOTAL' ELSE IM.PUMJ_CD
         END) as PUMJ_CD
FROM . . .
GROUP BY H.ORDER_DATE,
         (CASE WHEN IM.PUMJ_CD IN ('BF','BR') THEN 'TOTAL' ELSE IM.PUMJ_CD
          END)

这与你想要的有点不同。对于这两个值，它将始终返回TOTAL。

如果您想要个人价值，可以稍作修改：

SELECT  H.ORDER_DATE as [Order Date],
        SUM(D.WORK_QTY) as [Work Qty],
        SUM(TD. TRAN_QTY) as [Transaction Qty],
        (CASE WHEN COUNT(*) = 1 THEN MIN(IM.PUMJ_CD)
              ELSE (CASE WHEN IM.PUMJ_CD IN ('BF','BR') THEN 'TOTAL' ELSE IM.PUMJ_CD)
         END) as PUMJ_CD
FROM . . .
GROUP BY H.ORDER_DATE,
         (CASE WHEN IM.PUMJ_CD IN ('BF','BR') THEN 'TOTAL' ELSE IM.PUMJ_CD
          END)

Answer 2

在两个数据集上使用Union。

1 - 没有BR和BF
2 - 仅BR和BF为总计

SELECT  H.ORDER_DATE 'Order Date',
        SUM(D.WORK_QTY) 'Work Qty',
        SUM(TD. TRAN_QTY) 'Transaction Qty',
        IM.PUMJ_CD

FROM [dbo].[ORDER_HEADER] H

    LEFT JOIN ORDER_DETAIL D ON D.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_HEADER T ON T.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_DETAIL TD ON TD.TRAN_ID = T.TRAN_ID
    LEFT JOIN TRAN_TYPE TT ON TT.TRAN_TYPE_ID = TD.TRAN_TYPE_ID 
    LEFT JOIN ITM_MST IM ON IM.ITM_NM = D.ITEM_NAME

WHERE   TD.TRAN_TYPE_ID = '231' 
        AND PUMJ_CD IN  ('SHFT','BJ','TJ')  -- NO BR BF
        AND H.ORDER_DATE BETWEEN '20170403' AND '20170407'

GROUP BY    IM.PUMJ_CD,
            H.ORDER_DATE

union

SELECT  H.ORDER_DATE,
        SUM(D.WORK_QTY),
        SUM(TD. TRAN_QTY),
        'TOTAL'

FROM [dbo].[ORDER_HEADER] H

    LEFT JOIN ORDER_DETAIL D ON D.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_HEADER T ON T.ORDER_ID = H.ORDER_ID
    LEFT JOIN TRAN_DETAIL TD ON TD.TRAN_ID = T.TRAN_ID
    LEFT JOIN TRAN_TYPE TT ON TT.TRAN_TYPE_ID = TD.TRAN_TYPE_ID 
    LEFT JOIN ITM_MST IM ON IM.ITM_NM = D.ITEM_NAME

WHERE   TD.TRAN_TYPE_ID = '231' 
        AND PUMJ_CD IN ('BF','BR')  -- ONLY BF AND BR AS TOTAL
        AND H.ORDER_DATE BETWEEN '20170403' AND '20170407'

GROUP BY   H.ORDER_DATE

如何根据列的值对记录集的总和求和？

2 个答案: