嘿大家我的问题相对简单,我每次点击屏幕左侧时如何获得两个块切换位置...就像我点击两个块切换位置一样,然后如果我再次点击他们回到他们的初始位置(在某种意义上转回)然后他们继续每次敲击。
下图包含我的游戏场景,忽略蓝色和黄色块,红色块的初始位置是x:0,y:475,绿色块的初始位置是x:0,y:550 < / p>
每次触摸屏幕左侧时,我都需要帮助切换块位置。
//These are my actions...
let topUnderBlockSwitch = SKAction.moveTo(y: 550, duration: 0.1)
let topAboveBlockSwitch = SKAction.moveTo(y: 475, duration: 0.1)
let bottomUnderBlockSwitch = SKAction.moveTo(y: -475, duration: 0.1)
let bottomTopBlockSwitch = SKAction.moveTo(y: -550, duration: 0.1)
override func touchesBegan(_ touches: Set<UITouch>, with event: UIEvent?) {
for touch in touches {
let location = touch.location(in: self)
if location.x < 0 {
if greenBlock.position.y == 550 {
redBlock.run(topUnderBlockSwitch)
greenBlock.run(topAboveBlockSwitch)
} else if greenBlock.position.y == 475 {
redBlock.run(topUnderBlockSwitch)
greenBlock.run(topAboveBlockSwitch)
}
} else if // the rest of the code for the right side...
答案 0 :(得分:1)
这个怎么样:
redBlock.run(SKAction.moveTo(y:greenBlock.position.y, duration:0.1))
greenBlock.run(SKAction.moveTo(y:redBlock.position.y, duration:0.1))
然后你不必在多个地方硬编码坐标。