我正在开发一个程序,我从图像的一部分中获取RGB值。我想去除颜色中的黑暗并使其变亮。我的工作是使用<?php
echo system("echo 'm' > /dev/ttyAMA0");
sleep(2);
echo system("echo '1' > /dev/ttyAMA0");
sleep(2);
echo system("echo '2' > /dev/ttyAMA0");
sleep(2);
echo system("echo '3' > /dev/ttyAMA0");
sleep(2);
echo system("echo '4' > /dev/ttyAMA0");
sleep(2);
echo system("echo '5' > /dev/ttyAMA0");
sleep(2);
echo system("echo '6' > /dev/ttyAMA0");
?>
然后我使用亮度通道并将其设置为范围内的最高值,然后将HSB转换回RGB。但是,当我这样做时,颜色会完全改变。这是一个深红色的示例,它变成紫色,我用这个代码。
Color.RGBtoHSB
输出:
System.out.println("Before Conversion:");
System.out.println("R: " + rAvg + "\nG :" + gAvg + "\nB :" + bAvg);
Color.RGBtoHSB(rAvg, gAvg, bAvg, hsv);
hsv[2] = 100; //Set to max value
System.out.println("H: " + hsv[0] * 360 + "\nS: " + hsv[1] * 100 + "\nV :" + hsv[2]);
int rgb = Color.HSBtoRGB(hsv[0], hsv[1], hsv[2]);
System.out.println("After conversion");
Color color = new Color(rgb);
System.out.println("R: " + color.getRed());
System.out.println("G: " + color.getGreen());
System.out.println("B: " + color.getBlue());
答案 0 :(得分:2)
亮度hsv[2]
需要是介于0和1之间的值。尝试以下两行代码:
hsv[2] = 1; //Set to max value
System.out.println("H: " + hsv[0] * 360 + "\nS: " + hsv[1] * 100 + "\nV :" + hsv[2] * 100);