Question

检查数组的总和是否小于最大时间，如果是，则随机数的生成器将停止，输出将如下：

No of customer = 3     
max time = 4;          
customer 1 = 3     
customer 2 = 1          
total time = 4          
//so the customer 3 a

class CstplangsBadango

package cstplangsbadango;

import java.io.*;
import java.util.Random;
import java.util.Scanner;

public class CstplangsBadango {


    static int customer = 0;
    static int maxTime = 0;

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        Random rand = new Random();

        System.out.print("Enter number of customer: ");
        customer = sc.nextInt();

        System.out.print("Enter number of Maximum time: ");
        maxTime = sc.nextInt();
        System.out.println(" ");

        int[] cust = new int[customer];
        int j = 0;
        int sum = 0;
        int sum1 = 0;
        int chu = 0;
        for (int i = 0; i < cust.length; i++) {

            cust[i] = (int) randomFill();

            j += 1;
            sum += cust[i];
            System.out.println("Customer #" + j + " = " + cust[i]);    

        }

        System.out.println(" ");
        System.out.println("Maximum time: " + sum);


    }

    public static double randomFill() {

        Random rand = new Random();
        int randomNum = rand.nextInt(3) + 1;
        return randomNum;
    }

    }

Answer 1

for (int i = 0; i < cust.length; i++) {
    cust[i] = (int) randomFill();
}

for (int i = 0; i < cust.length; i++) { 
    int newSum = sum + cust[i];

    if (sum < maxTime) {
        sum = newSum;
    } else if(sum == maxTime) {
        sum = newSum;
        break;
    } else {
        break;
    }

    j++;
    System.out.println("Customer #" + j + " = " + cust[i]);

}

Answer 2

您必须排除声明

j+=1;
sum += cust[i];
System.out.println("Customer #" + j + " = " + cust[i])

并在填充数组时在创建的循环下创建另一个循环

for(int i=0;i<cust.length;++i)
{
        j+=1;
        sum+=cust[i];
        if(sum>=MAX_TIME)
        {
           i=cust.length;
           System.out.println("Customer #" + j + " = " + cust[i]);
        }

}

if(sum>MAX_TIME)
{
   int subtractor=sum-MAX_TIME;
   sum-=subtractor;
}

检查数组的总和必须小于最大时间

2 个答案: