Question

我一直试图在别处找到答案，但要么我不理解解释，要么解决方案对我的情况不起作用。

因此对于这种情况：
1.输出字符是中文
2.阅读部分工作完全正常，只是书写故障 3.我正在使用Python 2.7.13

请帮忙！

顺便说一下，我对python很新，所以如果你找到任何可以通过使用任何更好的实践来改进的东西，请指出它们！我真的很感激！

谢谢！

以下是代码：

# -*- coding: utf-8 -*-
import csv
import urllib2
from bs4 import BeautifulSoup
import socket
import httplib
# import sys  <= this did not work
# reload(sys)
# sys.setdefaultencoding('utf-8')

with open('/users/Rachael/Desktop/BDnodes.csv', 'r') as readcsv, 
open("/users/Rachael/Desktop/CheckTitle.csv", 'wb') as writecsv:
    writer = csv.writer(writecsv)
    for row in readcsv.readlines():
        opener = urllib2.build_opener()
        opener.addheaders = [('User-Agent',
                          'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/36.0.1941.0 Safari/537.36')]
        urllib2.install_opener(opener)
        openpage = urllib2.urlopen(row).read()
        soup = BeautifulSoup(openpage, "lxml")
        # print "page results:"
        for child in soup.findAll("h3", {"class": "t"}):
            try:
                geturls = child.a.get('href')
                # print urllib2.urlopen(geturls).geturl()
                url_result = urllib2.urlopen(geturls).geturl()
                # print url_result
                try:
                    openitem = urllib2.urlopen(url_result).read()
                    gettitle = BeautifulSoup(openitem, 'lxml')
                    url_title = gettitle.title.text
                except urllib2.HTTPError:
                    url_title = 'passed http error'
                    pass
                except urllib2.URLError:
                    url_title = 'passed url error'
                    pass
                except socket.timeout:
                    url_title = 'passed timeout'
                    pass
                except httplib.BadStatusLine:
                   url_title = 'passed badstatus'
                    pass
                except:
                    url_title = 'unknown'
                    pass
            except urllib2.HTTPError as e:
                pass
            except urllib2.URLError:
                pass
            except socket.timeout:
                pass
            except httplib.BadStatusLine:
                pass
            writer.writerow([url_result, url_title])
            # writer.writerow([url_result, url_title.encode('utf-8')]) did not work either, even tried with 'utf-16'
writecsv.close()

错误是：

C:\Python27\python.exe C:/Users/Rachael/PycharmProjects/untitled1/OpenNGet.py
Traceback (most recent call last):
  File "C:/Users/Rachael/PycharmProjects/untitled1/OpenNGet.py", line 55, in <module>
    writer.writerow([url_result, url_title])
UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-2: ordinal not in range(128)

Process finished with exit code 1

Answer 1

您可以在open函数中传递编码参数。

import codecs
codecs.open("/users/Rachael/Desktop/CheckTitle.csv", 'wb', encoding='utf-8') as writecsv

Answer 2

您的原始解决方案是否正确，但问题出在“结果”变量而不是标题中？

尝试类似

的内容

writer.writerow([url_result.encode('utf-8'), url_title.encode('utf-8')])

使用python编写csv时出错，可能是unicode / encode / decode问题

2 个答案: