以下是我目前拥有的代码(它不起作用,因为最后一个块看到数组是未定义的,它是为了显示我想要做的事情)
IEnumerable<string> sponsorshipQuery1 =
from runner1 in venueQuery6.Descendants("Runner")
where (int)runner1.Element("Sponsorship") > 0
orderby (int)runner1.Element("Sponsorship") descending
select runner1.Element("Firstname").Value;
IEnumerable<string> sponsorshipQuery2 =
from runner1 in venueQuery6.Descendants("Runner")
where (int)runner1.Element("Sponsorship") > 0
orderby (int)runner1.Element("Sponsorship") descending
select runner1.Element("Sponsorship").Value;
string[] nameArray;
string[] moneyArray;
foreach (string name in sponsorshipQuery1)
{
nameArray = sponsorshipQuery1
.OfType<object>()
.Select(o => o.ToString()).ToArray();
}
foreach (string money in sponsorshipQuery2)
{
moneyArray = sponsorshipQuery2
.OfType<object>()
.Select(o => o.ToString())
.ToArray();
}
Console.WriteLine("All sponsorship money raised in descending order:");
for (int i = 0; i < nameArray.Length; i++)
{
Console.WriteLine(nameArray[i] + " has raised £" + moneyArray[i]);
}
理想情况下,我希望能够在底部执行for循环。我猜想要替换两个foreach循环并使它们成为KeyValuePairs但我不知道该怎么做。
我也是使用Linq查询的新手,所以我混合使用查询语法和=&gt;语法是因为我教过查询语法,但我也在尝试在互联网上找到的代码。
答案 0 :(得分:6)
从您的示例代码中可以看出,您可以在一个查询中获取这两个值,并将它们保存为匿名类型:
var results = from runner1 in venueQuery6.Descendants("Runner")
where (int)runner1.Element("Sponsorship") > 0
orderby (int)runner1.Element("Sponsorship") descending
select new {
Name = runner1.Element("Firstname").Value,
Amount = runner1.Element("Sponsorship").Value
};
然后你可以循环这些结果:
foreach (var result in results)
{
Console.WriteLine(result.Name + " has raised £" + result.Amount);
}
答案 1 :(得分:2)
串联迭代两个序列的最高级方法是使用Zip
。要获得KeyValuePair
,请使用
sponsorshipQuery1.Zip(sponsorshipQuery2, (k, v) => new KeyValuePair<string, string>(k, v))
虽然我可能根本不会使用KeyValuePair
,但是我的任务或匿名类型更具体,除非我真正关心它作为键和值对。
迭代你已经涵盖过的两个阵列。要对两个foreach
进行双重IEnumerable<T>
无法(必然)编入索引,需要将至少一个循环分解为其组件MoveNext()
和{{ 1}}
Current
在您的特定示例中,因为您有一个共同的来源:
using (var en1 = sponsorshipQuery1.GetEnumerator())
{
foreach(var item2 in sponsorshipQuery2)
{
if (!en1.MoveNext())
{
break;
}
var item1 = en.Current;
// Do something with the two items here. E.g.
}
}
我只是from runner1 in venueQuery6.Descendants("Runner")
where (int)runner1.Element("Sponsorship") > 0
orderby (int)runner1.Element("Sponsorship") descending
开始。