Question

编写一个函数collect_sims（nsim，N，D，p = 0.5，nmax = 10000）运行run_sim函数nsim次（带参数N，D，p）并返回一个长度为nmax的numpy数组，给出的数量为模拟采取指定步骤停止的次数。例如，假设nsim为8，run_sim的连续运行为您提供3,4,4,3,6,5,4,4。您可以将其列为“两个3，四个4，一个5，一个6，零7，零8 ...”

def collect_sims(nsim, N, D, p=0.5, nmax=10000):
    run_sim(N=20, D=6, p=0.5, itmax=5000)
    onecount = 0
    twocount = 0
    threecount = 0
    fourcount = 0
    fivecount = 0
    sixcount = 0
    for k in range (n):
        if D == 1:
            onecount += 1
        if D == 2:
            twocount += 1
        if D == 3:
            threecount += 1
        if D == 4:
            fourcount += 1
        if D == 5:
            fivecount += 1
        if D == 6:
            sixcount += 1

return(k)

print(onecount, "1",twocount,"2",threecount,"3",fourcount,"4",fivecount,"5",sixcount,"6")

它说我的6个变量onecount，twocount等没有定义，我该如何定义它们？另外，我该怎么做才能修复我的代码？

Answer 1

我不知道你为什么要回来k。

无论如何，问题是oncount，twocount，...等在打印的不同范围内。您可以将print（）放在函数中，也可以返回带有计数的元组

有些人喜欢这样：

def collect_sims(nsim, N, D, p=0.5, nmax=10000):
    run_sim(N=20, D=6, p=0.5, itmax=5000)
    onecount = 0
    twocount = 0
    threecount = 0
    fourcount = 0
    fivecount = 0
    sixcount = 0
for k in range (n):
    if D == 1:
       onecount += 1
    if D == 2:
       twocount += 1
    if D == 3:
       threecount += 1
    if D == 4:
       fourcount += 1
    if D == 5:
       fivecount += 1
    if D == 6:
       sixcount += 1

return(onecount, twocount, threecount, fourcount,fivecount,sixcount)

onecount, twocount, threecount, fourcount,fivecount,sixcount = collect_sims (...)

print(onecount, "1",twocount,"2",threecount,"3",fourcount,"4",fivecount,"5",sixcount,"6")

不同解决方案

也许这个其他解决方案可以帮到你：

https://stackoverflow.com/a/9744274/6237334

Answer 2

缩进 for 循环：在您发布的代码中，它返回原始缩进级别（无<，用于语句）。这结束了你的功能，循环在主程序中。您的变量尚未定义（因为它们与函数中的变量不同），而您的返回是非法的。

或许试试这个？

def collect_sims(nsim, N, D, p=0.5, nmax=10000):
    run_sim(N=20, D=6, p=0.5, itmax=5000)
    onecount = 0
    twocount = 0
    threecount = 0
    fourcount = 0
    fivecount = 0
    sixcount = 0
    for k in range (n):
        if D == 1:
            onecount += 1
        if D == 2:
            twocount += 1
        if D == 3:
            threecount += 1
        if D == 4:
            fourcount += 1
        if D == 5:
            fivecount += 1
        if D == 6:
            sixcount += 1

    print(onecount, "1",twocount,"2",threecount,"3",fourcount,"4",fivecount,"5",sixcount,"6")

collect_sims()

我无法测试，因为您没有提供足够的代码。另请注意，我只是将 print 语句保留为调试跟踪。你必须返回一个阵列，而你还没有尝试过这样做。您的原始代码返回 k ，必须为n + 1。这对调用程序没用。

进一步提供帮助

学习使用6个元素的列表作为计数，而不是六个单独的变量。更好的是，将所有模具卷放入一个列表中，只需使用计数功能来确定每个模具的数量。

Python骰子结果计数

2 个答案: