Question

使用SQL Server 2014.我有一个带有时间戳的记录列表，我想计算每小时有多少记录，然后计算每天记录计数超过给定数量的小时数，比如20。

这是我到目前为止所拥有的：

select count(distinct datepart(hour, convert(datetime, OrderStateDate))) Count_HoursOver,
    datepart(YEAR, convert(datetime, OrderStateDate)) Date_YEAR,
    datepart(month, convert(datetime, OrderStateDate)) Date_MONTH,
    datepart(day, convert(datetime, OrderStateDate)) Date_DAY
from Reporting.dbo.Orders
group by datepart(YEAR, convert(datetime, OrderStateDate)),
    datepart(month, convert(datetime, OrderStateDate)),
    datepart(day, convert(datetime, OrderStateDate))
having count(idscript) >= 20

结果不正确，我无法理解返回的内容和原因。我不正确地使用HAVING吗？任何建议将不胜感激！

Answer 1

你在这里有两个部分的问题

我想计算每小时有多少记录

您可以创建一个返回元组（RecordsPerHour，HOUR，YEAR，MONTH，DAY）的查询，如下所示：

SELECT 
    count(*) as RecordsPerHour, 
    datepart(hour,convert(datetime,OrderStateDate)) as Date_HOUR, 
    datepart(year,convert(datetime,OrderStateDate)) as Date_YEAR,
    datepart(month,convert(datetime,OrderStateDate)) as Date_MONTH,
    datepart(day,convert(datetime,OrderStateDate)) as Date_DAY
FROM Reporting.dbo.Orders
GROUP BY
    datepart(year,convert(datetime,OrderStateDate)),
    datepart(month,convert(datetime,OrderStateDate)),
    datepart(day,convert(datetime,OrderStateDate)),
    datepart(hour,convert(datetime,OrderStateDate))

然后计算每天记录计数超过给定数量的小时数，比如20

要执行此操作，请在嵌套查询中使用问题第一部分中的查询，使用HAVING子句仅过滤包含至少20个订单的小时数。

在外部查询上，按（年，月，日）分组以确定当天至少有20个订单的小时数：

SELECT
    count(*) as HoursWithAtLeast20Orders, 
    Date_YEAR,
    Date_MONTH,
    Date_DAY
FROM
    (SELECT 
        datepart(hour,convert(datetime,OrderStateDate)) as Date_HOUR, 
        datepart(year,convert(datetime,OrderStateDate)) as Date_YEAR,
        datepart(month,convert(datetime,OrderStateDate)) as Date_MONTH,
        datepart(day,convert(datetime,OrderStateDate)) as Date_DAY
    FROM Reporting.dbo.Orders
    GROUP BY
        datepart(year,convert(datetime,OrderStateDate)),
        datepart(month,convert(datetime,OrderStateDate)),
        datepart(day,convert(datetime,OrderStateDate)),
        datepart(hour,convert(datetime,OrderStateDate))
    HAVING count(*) >=20) as t
GROUP BY
    Date_YEAR,
    Date_MONTH,
    Date_DAY

Answer 2

第一轮到第一轮，然后是第二轮

SELECT 
   count(*) as [hours with 20+ Orders],
   dateadd(day, datediff(day,'20000101',dt_hour_rounded),'20000101') as dt_day_rounded     
FROM (
   SELECT
      count(*) as OrdersInHour,
      dateadd(hour, datediff(hour,'20000101',OrderStateDate),'20000101') as dt_hour_rounded
   FROM Reporting.dbo.Orders
   GROUP BY dateadd(hour, datediff(hour,'20000101',OrderStateDate),'20000101')
) t
GROUP BY dateadd(day,datediff(day,'20000101',dt_hour_rounded),'20000101')
WHERE OrdersInHour >= 20

SQL用于计算每小时的记录数，并计算总记录数大于一个值的小时数

2 个答案: