Question

我发现了类似于我想要的东西here，但它并没有给出正确的输出，而且我正试图想出正确的解决方案......

我们有一个AVS服务器（实时帐户验证服务，但这是无关紧要的），我想知道今天（或任何其他日子）每小时有多少请求。例如，假设在上午8点到9点之间发出了100个请求，并且在9点到10点之间发出了50个请求。输出在 8AM 时应 100 ， 9AM 时 150 ，但我的查询显示的是请改为每小时一次。

我可以看到它为什么这样做......它是分组小时所以它向我显示每小时的请求，但这不是我想要的，这是每小时的总运行。（所以我每天都可以运行它，看看昨天这个请求的数量是什么样的等等......并且可以看出这是一个缓慢或快速的一天。）我该怎么做？

DECLARE @CurrentDate DATETIME = '14 nov 2014'

SELECT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour],
    COUNT(ID) [Requests] 
FROM Request 
WHERE 
    DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate)
GROUP BY
    CAST(DateCreated AS DATE),
    DATEPART(hour, DateCreated)
ORDER BY 
    CAST(DateCreated AS DATE)

Answer 1

以下内容应该有效

DECLARE @CurrentDate DATETIME = '13 nov 2014'

SELECT DISTINCT 
    CAST(DateCreated AS DATE) [Date], 
    DATEPART(hour,DateCreated) [Hour],
    COUNT(ID) OVER (ORDER BY DATEPART(hour, DateCreated))
FROM Request
WHERE 
    DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate)
ORDER BY 
    DATEPART(hour, DateCreated)

Answer 2

感谢您的所有答案。他们中没有一个完全符合我的要求，所以这是我的最终查询，以防它可以帮助某人。答案的问题，也可能是我的问题，结果只显示每小时的总请求数，而不是当天的最终总数。我的下面的查询给出了每小时的请求，以及当天的最终请求，或当前总数（如果是当天）。

DECLARE @CurrentDate DATETIME = '17 Nov 2014'

SELECT * FROM ( 
    SELECT DISTINCT 
        CAST(DateCreated AS DATE) [Date],
        CASE
            WHEN LEN(CAST(DATEPART(hour,DateCreated) AS VARCHAR)) = 1 THEN '0' + CAST(DATEPART(hour,DateCreated) AS VARCHAR)
            ELSE CAST(DATEPART(hour,DateCreated) AS VARCHAR)
        END + ':00:00' [Time],
        rank() OVER (ORDER BY DATEPART(hour, DateCreated))[Requests]
    FROM Request
    WHERE 
        DateCreated >= @CurrentDate AND DateCreated < DATEADD(DAY, 1, @CurrentDate)
    UNION   
    SELECT  
        CAST(@CurrentDate AS DATE),
        CONVERT(VARCHAR(8),
                (SELECT TOP 1 DateCreated FROM Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate) ORDER BY DateCreated DESC),
                108),
        (SELECT COUNT(*) from Request WHERE DateCreated >= @CurrentDate AND Request.DateCreated < DATEADD(DAY, 1, @CurrentDate))
        ) t
WHERE t.Requests > 0         
ORDER BY t.Time

今天运行查询会产生如下输出：

+------------+----------+----------+
|    Date    |   Time   | Requests |
+------------+----------+----------+
| 2014-11-17 | 07:00:00 |        1 |
| 2014-11-17 | 08:00:00 |        9 |
| 2014-11-17 | 09:00:00 |       49 |
| 2014-11-17 | 10:00:00 |      113 |
| 2014-11-17 | 11:00:00 |      225 |
| 2014-11-17 | 12:00:00 |      294 |
| 2014-11-17 | 13:00:00 |      363 |
| 2014-11-17 | 13:09:46 |      383 |
+------------+----------+----------+

Answer 3

DECLARE @CurrentDate DATETIME = '14 nov 2014';

WITH hourValues(hourVal) as (
    select  distinct cast(convert(varchar(14), @CurrentDate, 120) + '00' as datetime)
    from    [Request]
    where   datediff(day, [DateCreated], @CurrentDate) = 0)
SELECT 
    CAST(DateCreated AS DATE) [Date], 
    hourVal,
    COUNT(case when [DateCreated] < dateadd(hour, 1, hourVal) then 1 else null end) [Requests] 
FROM Request, hourValues
WHERE 
    datediff(day, [DateCreated], @CurrentDate) = 0
GROUP BY
    CAST(DateCreated AS DATE),
    hourVal
ORDER BY 
    [Date],
    HourVal

Answer 4

     --if you use MS SQL Server 2008 R2 or later version (2012/2014) then try this

DECLARE @CurrentDate DATE = CONVERT(DATE, GETDATE() - 1) , --yesterday
    @FinishDate AS DATE = CONVERT(DATE, GETDATE() + 1) --tomorrow

SELECT  DISTINCT
        CONVERT(DATE, DateCreated) AS [Date] ,
        DATEPART(HOUR, DateCreated) AS [Hour] ,
        COUNT(ID) OVER ( PARTITION BY CONVERT(DATE, DateCreated) ORDER BY DATEPART(HOUR,
                                                              DateCreated) ) AS [Cumulative Count]
FROM    Request
WHERE   CONVERT(DATE, DateCreated) BETWEEN @CurrentDate
                                   AND     @FinishDate
ORDER BY CONVERT(DATE, DateCreated) ,
        DATEPART(HOUR, DateCreated)

SQL选择每天的总计数，但按日期和小时分组（每小时运行总计）

4 个答案: