密码翻译

Question

我一直在尝试做这个小项目，在那里我制作一个程序，用户将输入三个氨基酸，如＃34; ATC＆＃34;作为回报，程序会告诉它，它的蛋白质，但我写的东西似乎没有做我想要的东西

Codon = print(input(str("Please enter your codon: ")))
if Codon == ("ATT", "ATC", "ATA"):
    print("Isoleucine")
elif Codon == ("CTT", "CTC", "CTA", "CTG", "TTA", "TTG"):
    print("Leucine")
elif Codon == ("GTT", "GTC", "GTA", "GTG"):
    print("Valine")
elif Codon == ("TTT", "TTC"):
    print("Phenylalanine")
elif Codon == "ATG":
    print("Methionine")
elif Codon == ("TGT", "TGC"):
    print("Cysteine")
elif Codon == ("GCT", "GCC", "GCA", "GCG"):
    print("Alanine")
elif Codon == ("GGT", "GGC", "GGA", "GGG"):
    print("CodonGlycine")
elif Codon == ("CCT", "CCC", "CCA", "CCG"):
    print("Proline")
elif Codon == ("ACT", "ACC", "ACA", "ACG"):
    print("Threonine")
elif Codon == ("TCT", "TCC", "TCA", "TCG", "AGT", "AGC"):
    print("Serine")
elif Codon == ("TAT", "TAC"):
    print("Tyrosine")
elif Codon == "TGG":
    print("Tryptophan")
elif Codon == ("CAA", "CAG"):
    print("Glutamine")
elif Codon == ("AAT", "AAC"):
    print("Asparagine")
elif Codon == ("CAT", "CAC"):
    print("Histidine")
elif Codon == ("GAA", "GAG"):
    print("Glutamic_Acid")
elif Codon == ("GAT", "GAC"):
    print("Aspartic_Acid")
elif Codon == ("AAA", "AAG"):
    print("Lysine")
elif Codon == ("CGT", "CGC", "CGA", "CGG", "AGA", "AGG"):
    print("Arginine")
elif Codon == ("TAA", "TAG", "TGA"):
    print("Stop_Codons")
else:print("Something Went Wrong")

此输出：

  

Please enter your codon: TGA TGA Something Went Wrong

我想要输出的内容：

Stop_Codon

任何建议/帮助都会非常感激 此外，我需要这样做它也可以接受小写字母，在这个阶段，如果要输入一个小写密码，它就不会按预期工作！

Answer 1

如果你写：

if Codon == ("ATT", "ATC", "ATA"):

Python将检查Codon（a str ing）是否等于到包含这三个元素的元组。现在由于类型不相等，它将与测试不匹配。您需要in来检查Codon（例如"ATC"）在元组中是否 。所以：

if Codon in ("ATT", "ATC", "ATA"):
#        ^ use in

此外你写道：

Codon = print(input(str("Please enter your codon: ")))
#       ^ print??

现在print打印输入，返回None 。所以你应该把它重写为：

Codon = input(str("Please enter your codon: ")).strip()
#                                               ^ strip the new line

然而，你最好使用dict离子。