Question

我编写了一个程序，以单个链表的形式乘以两个多项式。我无法使用此代码打印输出。

我得到的输出是

1st Number: 5x^2 + 4x^1 + 2x^0
2nd Number: 5x^1 + 5x^0
Multiplied polynomial:

我该如何解决？

我的代码：

// C++ program for multiplication of two polynomials
// using Linked Lists
#include<bits/stdc++.h>
using namespace std;

// Node structure containing power and coefficient of variable
struct node
{
    int coeff;
    int exp;
    struct node *next;
};
void padd(float, int, node**);          
// Function to create new node
void create_node(int x, int y, struct node **temp)
{
    struct node *r,*z ;
    z = *temp;
    if(z == NULL)
    {
        r =(struct node*)malloc(sizeof(struct node));
        r->coeff = x;
        r->exp = y;
        *temp = r;
        r->next = (struct node*)malloc(sizeof(struct node));
        r = r->next;
        r->next = NULL;
    }
    else
    {
        r->coeff = x;
        r->exp = y;
        r->next = (struct node*)malloc(sizeof(struct node));
        r = r->next;
        r->next = NULL;
    }
}

// Function Multiplying two polynomial numbers
void polymul ( struct node *poly1, struct node *poly2,
                   struct node *poly )
{
    struct node *y1 ;
    float coeff1;
    int exp1 ;

    y1 = poly2 ;  /* point to the starting of the second linked list */
if ( poly1 == NULL && poly2 == NULL )
        return ;

    /* if one of the list is empty */
if ( poly1 == NULL )
        poly = poly2 ;
    else
    {
        if ( poly2 == NULL )
            poly = poly1 ;
        else/* if both linked lists exist */

        {
            /* for each term of the first list */
            while ( poly1 != NULL )
            {
                /* multiply each term of the second linked list with a 
                    term of the first linked list */
                while ( poly2 != NULL )
                {
                    coeff1 = poly1 -> coeff * poly2 -> coeff ;
                    exp1 = poly1 -> exp + poly2 -> exp ;
                    poly2 = poly2 -> next ;

                    /* add the new term to the resultant polynomial */

                    padd ( coeff1, exp1, &poly ) ;
                }

                poly2 = y1 ;  /* reposition the pointer to the starting of
                         the second linked list */


                poly1 = poly1 -> next ;  /* go to the next node */

            }
        }
    }
}

/* adds a term to the polynomial in the descending order of the exponent */
void padd ( float coeff, int exp, struct node **s )
{
    struct node *r, *temp = *s ;

    /* if list is empty or if the node is to be inserted before the first node */
if ( *s == NULL || exp > ( *s ) -> exp )
    {
        *s=r = (struct node*) malloc ( sizeof ( struct node ) ) ;
        (*s) -> coeff = coeff ;
        (*s) -> exp = exp ;
        (*s)-> next = temp ;
    }
    else
    {
        /* traverse the entire linked list to search the position to insert a new node */
        while ( temp != NULL )
            {
                if ( temp -> exp == exp )
                {
                    temp -> coeff += coeff ;
                    return ;
                }

                if ( temp -> exp > exp && ( temp -> next -> exp < exp ||    temp -> next == NULL ) )
                    {
                        r = (struct node* )malloc ( sizeof ( struct node ) ) ;
                        r -> coeff = coeff;
                        r -> exp = exp ;
                        r -> next = temp -> next ;
                        temp -> next = r ;
                        return ;
                    }

            temp = temp -> next ;  /* go to next node */

            }

        r -> next = NULL ;
        temp -> next = r ;
    }
}

// Display Linked list
void show(struct node *node)
{
while(node->next != NULL)
    {
    printf("%dx^%d", node->coeff, node->exp);
    node = node->next;
    if(node->next != NULL)
        printf(" + ");
    }
}

// Driver program
int main()
{
    struct node *poly1 = NULL, *poly2 = NULL, *poly = NULL;

    // Create first list of 5x^2 + 4x^1 + 2x^0
    create_node(5,2,&poly1);
    create_node(4,1,&poly1);
    create_node(2,0,&poly1);

    // Create second list of 5x^1 + 5x^0
    create_node(5,1,&poly2);
    create_node(5,0,&poly2);

    printf("1st Number: "); 
    show(poly1);

    printf("\n2nd Number: ");
    show(poly2);

    poly = (struct node *)malloc(sizeof(struct node));

    // Function multiply two polynomial numbers
    polymul(poly1, poly2, poly);

    // Display resultant List
    printf("\nMultiplied polynomial: ");
    show(poly);

return 0;
}

Answer 1

您应该在函数padd()之前声明函数polymul，或者您可以在顶部编写函数原型，以便编译器知道{{1}之后将遇到函数padd }}

对于第二个错误，您应该将polymul函数的输出强制转换为malloc，因为malloc返回struct node *类型值。

只需将代码拼贴添加到代码中的void *函数中即可。

malloc

链表中有一些指针问题。我已将它们修改为ideone链接。

r = (struct node*)malloc ( sizeof ( struct node ) ) ;

Ideone Link

链表多项式乘法

1 个答案: