如何延迟算法的执行以直观地显示算法中每次迭代的结果?当我尝试更新下面代码中对象的高度时,它只显示最终结果。如何显示每一步发生的事情?
namespace BubbleSortRappresentazione_grafica
{
public partial class MainWindow : Window
{
int[] v;
public MainWindow()
{
InitializeComponent();
Random rnd = new Random();
v = new int[10];
for (int j = 0; j < 10; j++)
{
v[j] = rnd.Next(0, 100);
}
_0.Height = v[0] + 20;
_1.Height = v[1] + 20;
_2.Height = v[2] + 20;
_3.Height = v[3] + 20;
_4.Height = v[4] + 20;
_5.Height = v[5] + 20;
_6.Height = v[6] + 20;
_7.Height = v[7] + 20;
_8.Height = v[8] + 20;
_9.Height = v[9] + 20;
}
private void Button_Click(object sender, RoutedEventArgs e)
{
// algoritmo ordinamento
for (int i = 0; i < 10; i++)
{
for (int j = 0; j < 10; j++)
{
if (v[j] > v[i])
{
int tmp = v[j];
v[j] = v[i];
v[i] = tmp;
_0.Height = v[0] + 20;
_0.Content = v[0];
_1.Height = v[1] + 20;
_1.Content = v[1] ;
_2.Height = v[2] + 20;
_2.Content = v[2];
_3.Height = v[3] + 20;
_3.Content = v[3] ;
_4.Height = v[4] + 20;
_4.Content = v[4];
_5.Height = v[5] + 20;
_5.Content = v[5];
_6.Height = v[6] + 20;
_6.Content = v[6];
_7.Height = v[7] + 20;
_7.Content = v[7];
_8.Height = v[8] + 20;
_8.Content = v[8];
_9.Height = v[9] + 20;
_9.Content = v[9];
Thread.Sleep(100);
}
}
}
}
}
}
答案 0 :(得分:0)
我相信你真正想要的是Application.DoEvents方法:
.Sleep()
这将导致您在循环内进行的任何视觉更改都将在每次迭代中应用。你也可以考虑删除@SpringBootApplication
//@ImportResource({"classpath:dubbo.xml"})
//I want to specify the xml file with command line arguments at run time
public class App {
public static void main(String[] args) {
// How to import the XML file now?
SpringApplication.run(App.class, args);
}
}
,因为我不确定它对你有多大用处。