所以我试图获取.json文件并在c#中读取它,然后修改其中一个值,然后刷新.json文件以便更改该值。我知道如何读取文件,以及如何覆盖文件,但如何更改文件中某个特定项的特定值?
此脚本的目标是创建一个库存系统,其中可以通过json文件记录余额。我想使用BalanceChange()函数转到文件,使用ID变量找到正确的项目,然后相应地更改余额。
这是我的.json脚本:
[
{
"name":"Potion",
"id":1,
"balance":5
},
{
"name":"Neutral Bomb",
"id":2,
"balance": 4
}
]
这是我的c#脚本:
using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using System.IO;
using LitJson;
public class Item
{
public string Name { get; set; }
public int Id { get; set; }
public int Balance { get; set; }
public Item(string name1, int id1, int balance1) {
Name = name1;
Id = id1;
Balance = balance1;
}
}
public class InventoryAttempt : MonoBehaviour
{
public static void BalanceChange(string filePath, int ID, int change)
{
string jsonString = File.ReadAllText(Application.dataPath + filePath);
List<Item> itemList = JsonMapper.ToObject<List<Item>>(jsonString);
itemList [ID].Balance += change;
jsonString = JsonMapper.ToJson (itemList).ToString();
File.WriteAllText (Application.dataPath + filePath, jsonString);
}
void Start()
{
BalanceChange ("/Scripts/inventory.json", 1, -1);
}
}
此脚本由于某种原因无法运行。我一直收到这个错误:
MissingMethodException: Method not found: 'Default constructor not found...ctor() of Item'.
System.Activator.CreateInstance (System.Type type, Boolean nonPublic) (at /Users/builduser/buildslave/mono/build/mcs/class/corlib/System/Activator.cs:368)
System.Activator.CreateInstance (System.Type type) (at /Users/builduser/buildslave/mono/build/mcs/class/corlib/System/Activator.cs:254)
LitJson.JsonMapper.ReadValue (System.Type inst_type, LitJson.JsonReader reader)
LitJson.JsonMapper.ReadValue (System.Type inst_type, LitJson.JsonReader reader)
LitJson.JsonMapper.ToObject[List`1] (System.String json)
InventoryAttempt.BalanceChange (System.String filePath, Int32 ID, Int32 change) (at Assets/Scripts/InventoryAttempt.cs:26)
InventoryAttempt.Start () (at Assets/Scripts/InventoryAttempt.cs:34)
答案 0 :(得分:0)
是的,这就是这些图书馆的目的。我并不熟悉LitJson,但其中大部分都是相似的:
基于doucmentation示例;我们将json转换为对象,更改属性,然后再将其保存到json:
public class Person
{
// C# 3.0 auto-implemented properties
public string Name { get; set; }
public int Age { get; set; }
public DateTime Birthday { get; set; }
}
public class Example{
public static void JsonToPerson()
{
string json = @"
{
""Name"" : ""Thomas More"",
""Age"" : 57,
""Birthday"" : ""02/07/1478 00:00:00""
}";
Person thomas = JsonMapper.ToObject<Person>(json);
thomas.Age = 23;
string newJson = JsonMapper.ToJson(thomas);
}
}
要编辑属性,我们只需更改Objects属性即可。在我的例子中,我将thomas.Age编辑为23,然后再次将对象序列化为json。 应该给我们以下json:
{
""Name"" : ""Thomas More"",
""Age"" : 23,
""Birthday"" : ""02/07/1478 00:00:00""
}
如果您想在一个json中拥有多个Person,可以将它们添加到列表中并序列化列表。如果您希望每个不同对象都有唯一标识符,您可以在其中添加Id属性。像这样:
首先将Id属性添加到Person类:
public string Id { get; set; }
和用法/列表序列化:
List<Person> people = List<Person>();
Person thomas = new Person();
thomas.Name = "Thomas";
thomas.Id = "0001";
people.Add(thomas);
Person albert = new Person();
albert.Name = "Albert";
albert.Id = "0002";
people.Add(albert);
JsonMapper.ToJson(people);
这应该给你这样的Json:
{
{
""Name"" : ""Thomas"",
""Id"" : ""0001""
},
{
""Name"" : ""Albert"",
""Id"" : ""0002""
}
}