如何在Unity3D中使用LitJson编辑c#中的JSON值?

时间:2017-02-10 17:12:07

标签: c# json unity3d

所以我试图获取.json文件并在c#中读取它,然后修改其中一个值,然后刷新.json文件以便更改该值。我知道如何读取文件,以及如何覆盖文件,但如何更改文件中某个特定项的特定值?

此脚本的目标是创建一个库存系统,其中可以通过json文件记录余额。我想使用BalanceChange()函数转到文件,使用ID变量找到正确的项目,然后相应地更改余额。

这是我的.json脚本:

[
    {
    "name":"Potion",
    "id":1,
    "balance":5
    },
    {
    "name":"Neutral Bomb",
    "id":2,
    "balance": 4
    }
]

这是我的c#脚本:

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using System.IO;
using LitJson;


public class Item
{
    public string Name  { get; set; }
    public int Id       { get; set; }
    public int Balance  { get; set; }

    public Item(string name1, int id1, int balance1) {
        Name = name1;
        Id = id1;
        Balance = balance1;
    }
}

public class InventoryAttempt : MonoBehaviour
{
    public static void BalanceChange(string filePath, int ID, int change)
    {
        string jsonString = File.ReadAllText(Application.dataPath + filePath);
        List<Item> itemList = JsonMapper.ToObject<List<Item>>(jsonString);
        itemList [ID].Balance += change;
        jsonString = JsonMapper.ToJson (itemList).ToString();
        File.WriteAllText (Application.dataPath + filePath, jsonString);
    }

    void Start()
    {
        BalanceChange ("/Scripts/inventory.json", 1, -1);
    }
}

此脚本由于某种原因无法运行。我一直收到这个错误:

MissingMethodException: Method not found: 'Default constructor not found...ctor() of Item'.
System.Activator.CreateInstance (System.Type type, Boolean nonPublic) (at /Users/builduser/buildslave/mono/build/mcs/class/corlib/System/Activator.cs:368)
System.Activator.CreateInstance (System.Type type) (at /Users/builduser/buildslave/mono/build/mcs/class/corlib/System/Activator.cs:254)
LitJson.JsonMapper.ReadValue (System.Type inst_type, LitJson.JsonReader reader)
LitJson.JsonMapper.ReadValue (System.Type inst_type, LitJson.JsonReader reader)
LitJson.JsonMapper.ToObject[List`1] (System.String json)
InventoryAttempt.BalanceChange (System.String filePath, Int32 ID, Int32 change) (at Assets/Scripts/InventoryAttempt.cs:26)
InventoryAttempt.Start () (at Assets/Scripts/InventoryAttempt.cs:34)

1 个答案:

答案 0 :(得分:0)

是的,这就是这些图书馆的目的。我并不熟悉LitJson,但其中大部分都是相似的:

基于doucmentation示例;我们将json转换为对象,更改属性,然后再将其保存到json:

public class Person
{
    // C# 3.0 auto-implemented properties
    public string   Name     { get; set; }
    public int      Age      { get; set; }
    public DateTime Birthday { get; set; }
}


public class Example{
    public static void JsonToPerson()
    {
    string json = @"
        {
            ""Name""     : ""Thomas More"",
            ""Age""      : 57,
            ""Birthday"" : ""02/07/1478 00:00:00""
        }";

    Person thomas = JsonMapper.ToObject<Person>(json);

    thomas.Age = 23;

    string newJson = JsonMapper.ToJson(thomas);
    }
}

要编辑属性,我们只需更改Objects属性即可。在我的例子中,我将thomas.Age编辑为23,然后再次将对象序列化为json。 应该给我们以下json:

{
    ""Name""     : ""Thomas More"",
    ""Age""      : 23,
    ""Birthday"" : ""02/07/1478 00:00:00""
}

如果您想在一个json中拥有多个Person,可以将它们添加到列表中并序列化列表。如果您希望每个不同对象都有唯一标识符,您可以在其中添加Id属性。像这样:

首先将Id属性添加到Person类:

public string Id { get; set; }

和用法/列表序列化:

List<Person> people = List<Person>();

Person thomas = new Person();
thomas.Name = "Thomas";
thomas.Id = "0001";
people.Add(thomas);

Person albert = new Person();
albert.Name = "Albert";
albert.Id = "0002";
people.Add(albert);

JsonMapper.ToJson(people);

这应该给你这样的Json:

{
    {
        ""Name""     : ""Thomas"",
        ""Id""       : ""0001""
    },
    {
        ""Name""     : ""Albert"",
        ""Id""       : ""0002""
    }
}