Question

我希望获得容器内的所有值（比如dictionary）。容器可以具有嵌套对象，如dictionary, list, tuples and string值。目前我能够编写此代码以获取所有值，但它不处理列表项或对象本身就是序列的情况。

def get_all_values_in_container(search_dict):
    value_set = set()
    for key, value in search_dict.items():
        if isinstance(value, dict):
            results = get_all_values_in_container(value)
            for result in results:
                value_set.add(result)
        elif isinstance(value, (list, tuple)):
            for items in value: # Will fail if the item itself is a sequence
                value_set.add(items)
        else:
            value_set.add(value)

    return value_set

这是我的虚拟search_dict

    dummy = {'#text': ['Experience with build tools such as GRADLE, ANT or MAVEN; ',
           ' such as ',
           '. Experience with ',
           ' such as ',
           ', Subversion, or GIT. In depth knowledge of ',
           ' platforms Work experience with the following ',
           ', or ',
           '. Experience with build and ',
           '. Education/Certifications ',
           '. '],
 'area': 'RBA5000#LI SO1 Truven Health Analytics\n',
 'education': {'#text': ' degree in ',
               'degree': 'Bachelor s',
               'major': {'#text': 'Computer Science',
                         '@cipcode': '11.0701',
                         '@code': '0402',
                         '@std-major': 'COMPUTER SCIENCE'}},
 'interval': {'#text': ['or ', ' work experience in related field'],
              'area': 'comparable'},
 'skill': ['scripting languages',
           'Perl, UNIX shell',
           'SCM tools',
           'CVS',
           'Windows, UNIX',
           'technologies Oracle, SQL',
           'Informix; Java/J2EE; Cognos',
           'deployment automation tools like Jenkins',
           'preferred_skill',[{'preferred': 'Java/J2EE'}]]}

我知道这将是一个递归调用（可能是相同的函数或其他本身是递归的函数）。我该如何进一步继续

Answer 1

我想出了这个解决方案。截至目前，它工作正常（至少在我的测试用例中）

def get_all_values_in_container(container):
    value_set = set()
    if isinstance(container, (list, tuple, set)):
        for items in container:
            results = get_all_values_in_container(items)
            value_set.update(results)
    elif isinstance(container, dict):
        for key, value in container.items():
            results = get_all_values_in_container(value)
            value_set.update(results)
    else:
        value_set.add(get_processed_item(container))

    return value_set

任何人都可以提出可能失败的优势（我真的很期待这一点）。

获取容器内的所有值（具有嵌套列表和字典）

1 个答案: