Question

我有一个名为“high_low_teams_in_profile”的嵌套字典，如下所示：

{   
    m_profile1:
        {
            team_size1:
                {   
                    low: 1,

                    high: 1

                },
            team_size2:
                {   
                    low: 1,

                    high: 1

                }
        },
    m_profile2:
        {
            team_size1:
                {   
                    low: 1,

                    high: 1

                },
            team_size2:
                {   
                    low: 1,

                    high: 1

                }

        }   
}

我想得到{m_profile1：4，m_profile2：4}

在python中最有说服力的方法是什么？现在我有以下内容：

new_num_teams_in_profile = {}
for profile in high_low_teams_in_profile:
    new_num_teams_in_profile[profile]= dict((team_size, sum(high_low_teams_in_profile[profile][team_size].values())) for team_size in high_low_teams_in_profile[profile])

new_num_teams_in_profile= dict((profile, sum(new_num_teams_in_profile[profile].values())) for profile in new_num_teams_in_profile)

Answer 1

我不确定我是否说它是最Pythonic，但它是functional最多的：

p = high_low_teams_in_profile
{ prof:sum(p[prof][team][hl]
           for team in p[prof]
           for hl in p[prof][team])
  for prof in p}

sum的论点是generator expression，外{ prof:sum(...) for prof in p}是dictionary comprehension。

Answer 2

虽然这可能不是最pythonic，但以下代码应该可以工作，并且比原始版本更具可读性。请注意iteritems()方法，它允许访问dict的键和值，而itervalues()，顾名思义，只迭代dict的值。

final = {}
for key, sizes in high_low_teams_in_profile.iteritems():
    total = 0
    for value in sizes.itervalues():
        s = sum(value.itervalues())
        total += s

    final[key] = total

print final

此外，您可以使用以下内容。虽然行数较短，但阅读起来稍微困难一些。

final = {}
for key, sizes in high_low_teams_in_profile.iteritems():
    total = sum([sum(value.itervalues()) for value in sizes.itervalues()])
    final[key] = total

print final

Python：嵌套嵌套字典中不同字典内的值

2 个答案: