这个使用volatile的例子是否具有原子属性？

Question

我阅读了webrtc源代码，我找到了这段代码

 class AtomicOps {
 public:
  // Assumes sizeof(int) == sizeof(LONG), which it is on Win32 and Win64.
  static int Increment(volatile int* i) {
    return ::InterlockedIncrement(reinterpret_cast<volatile LONG*>(i));
  }
  static int Decrement(volatile int* i) {
    return ::InterlockedDecrement(reinterpret_cast<volatile LONG*>(i));
  }
  static int AcquireLoad(volatile const int* i) {
    return *i;
  }
  static void ReleaseStore(volatile int* i, int value) {
    *i = value;
  }
  static int CompareAndSwap(volatile int* i, int old_value, int new_value) {
    return ::InterlockedCompareExchange(reinterpret_cast<volatile LONG*>(i),
                                        new_value,
                                        old_value);
  }
  // Pointer variants.
  template <typename T>
  static T* AcquireLoadPtr(T* volatile* ptr) {
    return *ptr;
  }
  template <typename T>
  static T* CompareAndSwapPtr(T* volatile* ptr, T* old_value, T* new_value) {
    return static_cast<T*>(::InterlockedCompareExchangePointer(
        reinterpret_cast<PVOID volatile*>(ptr), new_value, old_value));
  }
};

我认为静态int AcquireLoad(volatile const int* i)函数没有原子属性？这是正确的吗？如果我是对的，为什么要使用volatile？