Question

我正在尝试随机更改字符串中的随机字符。程序还将决定随机变化的角色数量。编译器没有看到第二个for循环。我不知道为什么？再次感谢您

#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    char string[10];
    srand(time(NULL));
    int a;
    int count = 0;
    printf("Please enter string: ");
    scanf("%s", string);
    for (a = 0; string[a] != '\0'; a++) {
        count++;
    }
    printf("%d\n", count);
    for (int i = 0; i <= count; i + rand() % count) {
        string[i];
    }
    printf("String is: %s ", string);
}

Answer 1

要在单词中选择随机char并将其替换为随机char，您可以尝试以下操作。

#include <ctype.h>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    char string[10];
    srand(time(NULL));
    int a;
    int count = 0;
    printf("Please enter string: ");
    scanf("%s", string);
    for (a = 0; string[a] != '\0'; a++) {
        count++;
    }
    printf("%d\n", count);
    char randomletter = 'a' + (random() % 26);
    string[rand() % count] = randomletter;
    printf("String is: %s ", string);
}

测试

Please enter string: foobar
6
String is: fooiar

测试2

Please enter string: zoobar
6
String is: zolbar

编译器没有看到第二个for循环

1 个答案: