我试图创建一个基于三个给定长度在HTML画布中间绘制三角形的函数,我认为这将是HTML画布的简单介绍,我错了。
这是我到目前为止所处的地方,但两边都没有正确呈现:
function drawTriangle(sideOne, sideTwo, sideThree) {
var canvas = document.getElementById('triangle-canvas');
var ctx = canvas.getContext('2d');
var cx = canvas.width / 2;
var cy = canvas.height / 4;
var sideOneHeight = sideOne * (Math.sqrt(3) / 2);
var sideTwoHeight = sideTwo * (Math.sqrt(3) / 2);
ctx.beginPath();
ctx.moveTo(cx, cy);
ctx.lineTo(cx + 50, cy + sideOneHeight);
ctx.lineTo(cx - 50, cy + sideTwoHeight);
ctx.lineTo(cx, cy);
ctx.fill();
ctx.closePath();
}
有什么建议吗?
答案 0 :(得分:3)
设置Ax=0, Ay=0
,设置Bx=R3, By=0
。然后第三点满足两个圆方程
(Cx-Ax)² + (Cy-Ay)² = R2²
(Cx-Bx)² + (Cy-By)² = R1²
给出所选坐标的减少到
Cx² + Cy² = R2²
(Cx-R3)² + Cy² = R1²
和差异
2*Cx*R3 = R2²+R3²-R1²
允许从Cx
计算Cy
。
在代码中它看起来像这样:
var canvas = document.getElementById('triangle-canvas');
var ctx = canvas.getContext('2d');
var R1=120, R2=140, R3=90;
var Ax=0, Ay=0;
var Bx=R3, By=0;
var Cx=(R2*R1+R3*R3-R1*R1)/(2*R3);
var Cy=Math.sqrt(R2*R2-Cx*Cx);
var Ox = canvas.width / 2 - Bx/2;
var Oy = canvas.height / 2 + Cy/2;
ctx.beginPath();
ctx.moveTo(Ox+Ax, Oy-Ay);
ctx.lineTo(Ox+Bx, Oy-By);
ctx.lineTo(Ox+Cx, Oy-Cy);
ctx.closePath();
ctx.fillStyle="gold"; ctx.lineWidth=2;
ctx.stroke(); ctx.fill();

<canvas id='triangle-canvas' height=200 width=400></canvas>
&#13;
答案 1 :(得分:0)
var c = document.getElementById("myCanvas");
var ctx = c.getContext("2d");
ctx.font = "20px Times New Roman";
ctx.fillStyle = "black";
ctx.textAlign = "center";
ctx.strokeStyle = "black";
var canvasSize = [parseInt(c.width), parseInt(c.height)];
var _side_1 = 5, _side_2 = 3, _side_3 = 4; //All values are taken assuming as centimeter unit.
var factor = 37.7952755906;
var sides = [_side_1, _side_2, _side_3];
sides.sort(function(a, b){return a-b});
var halfPerimeter = (_side_1 + _side_2 + _side_3) / 2;
var area = Math.sqrt(halfPerimeter * (halfPerimeter - _side_1) * (halfPerimeter - _side_2) * (halfPerimeter - _side_3));
var height = ((2 * area) / sides[2]).toPrecision(5);
var slopeOfBase = Math.sqrt(Math.pow(sides[0], 2) - Math.pow(height, 2));
ctx.beginPath();
ctx.setLineDash([]);
ctx.moveTo((canvasSize[0]/2 - 0.5 * sides[2] * factor), (canvasSize[1]/2 + 0.5 * height * factor));
ctx.lineTo((canvasSize[0]/2 + 0.5 * sides[2] * factor), (canvasSize[1]/2 + 0.5 * height * factor));
ctx.fillText("c = " + sides[2] + " cm",(canvasSize[0]/2 - 0.5 * sides[2] * factor + canvasSize[0]/2 + 0.5 * sides[2] * factor) / 2,(canvasSize[1]/2 + 0.5 * height * factor + canvasSize[1]/2 + 0.5 * height * factor) / 2 + 15);
ctx.lineTo((canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor), (canvasSize[1]/2 - 0.5 * height * factor));
ctx.fillText("b = " + sides[0] + " cm",(canvasSize[0]/2 + 0.5 * sides[2] * factor + canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor) / 2 + 50,(canvasSize[1]/2 + 0.5 * height * factor + canvasSize[1]/2 - 0.5 * height * factor) / 2);
ctx.lineTo((canvasSize[0]/2 - 0.5 * sides[2] * factor), (canvasSize[1]/2 + 0.5 * height * factor));
ctx.fillText("a = " + sides[1] + " cm",(canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor + canvasSize[0]/2 - 0.5 * sides[2] * factor) / 2 - 50,(canvasSize[1]/2 - 0.5 * height * factor + canvasSize[1]/2 + 0.5 * height * factor) / 2);
ctx.stroke();
ctx.beginPath();
ctx.setLineDash([5]);
ctx.moveTo((canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor), (canvasSize[1]/2 - 0.5 * height * factor));
ctx.lineTo((canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor), (canvasSize[1]/2 + 0.5 * height * factor));
ctx.fillText("h = " + height + " cm",(canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor + canvasSize[0]/2 + 0.5 * sides[2] * factor - slopeOfBase * factor) / 2,(canvasSize[1]/2 - 0.5 * height * factor + canvasSize[1]/2 + 0.5 * height * factor) / 2 + 20);
ctx.stroke();
<canvas id="myCanvas" width="600" height="500"></canvas>