Question

我在网上搜索，但是在某些例子中，找不到合适的工作并执行我需要的简单任务，也许你可以帮助我。

我有一个对象数组：

for (int j = 0; j < blocks.Count; j++)
            {
                if (blocks[j].alive == false)
                {
                    blocks.RemoveAt(j);
                    break;
                }
            }
            for (int i = 0; i < blocks.Count; i++)
            {
                if (blocks[i].alive == false)
                {
                    blocks.RemoveAt(i);
                    break;
                }
            }

我正在寻找一个简单的直接解决方案，按年分组，然后按月分组，然后按照以下方式分组

结果应该是我可以迭代的东西，如下所示：

[
  {
    "date": "2015-01-01T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": false,
    "isCompleted": true,
    "size": 1024
  },
  {
    "date": "2015-01-02T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": false,
    "isCompleted": false,
    "size": 1024
  },
  {
    "date": "2015-02-01T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": true,
    "isCompleted": false,
    "size": 1024
  },
  {
    "date": "2015-02-02T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": false,
    "isCompleted": true,
    "size": 1024
  },
  {
    "date": "2016-04-01T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": true,
    "isCompleted": false,
    "size": 1024
  },
  {
    "date": "2016-04-02T12:00:00.000Z",
    "photoUrl": "",
    "inProgress": false,
    "isCompleted": true,
    "size": 1024
  }
]

最终目的是通过带有角度的ng-repeat在列表中检查它。

如果有人有任何建议我确定此代码对其他代码非常有用，因为没有关于采用平面日期数组并将其转换为年，月，日对象的示例，净。

非常感谢！

Answer 1

您可以检查是否设置了年份，如果没有，则指定一个包含空对象的数组。然后继续月份，然后将项目分配给它。

var data = [{ date: "2015-01-01T12:00:00.000Z", photoUrl: "", inProgress: false, isCompleted: true, size: 1024 }, { date: "2015-01-02T12:00:00.000Z", photoUrl: "", inProgress: false, isCompleted: false, size: 1024 }, { date: "2015-02-01T12:00:00.000Z", photoUrl: "", inProgress: true, isCompleted: false, size: 1024 }, { date: "2015-02-02T12:00:00.000Z", photoUrl: "", inProgress: false, isCompleted: true, size: 1024 }, { date: "2016-04-01T12:00:00.000Z", photoUrl: "", inProgress: true, isCompleted: false, size: 1024 }, { date: "2016-04-02T12:00:00.000Z", photoUrl: "", inProgress: false, isCompleted: true, size: 1024 }],
    grouped = Object.create(null);

data.forEach(function (a) {
    var year = a.date.slice(0, 4),
        month = ['JAN', 'FEB', 'MAR', 'APR', 'MAY', 'JUN', 'JUL', 'AUG', 'SEP', 'OCT', 'NOV', 'DEC'][a.date.slice(5, 7) - 1],
        day = a.date.slice(8, 10);

    grouped[year] = grouped[year] || [{}];
    grouped[year][0][month] = grouped[year][0][month] || [{}];
    grouped[year][0][month][0][day] = a;
});

console.log(grouped);

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Answer 2

Unfortunately, there doesn't seem to be a way to reduce this further as each level has different key/value requirements.

var data = [{"date":"2015-01-01T12:00:00.000Z","photoUrl":"","inProgress":false,"isCompleted":true,"size":1024},{"date":"2015-01-02T12:00:00.000Z","photoUrl":"","inProgress":false,"isCompleted":false,"size":1024},{"date":"2015-02-01T12:00:00.000Z","photoUrl":"","inProgress":true,"isCompleted":false,"size":1024},{"date":"2015-02-02T12:00:00.000Z","photoUrl":"","inProgress":false,"isCompleted":true,"size":1024},{"date":"2016-04-01T12:00:00.000Z","photoUrl":"","inProgress":true,"isCompleted":false,"size":1024},{"date":"2016-04-02T12:00:00.000Z","photoUrl":"","inProgress":false,"isCompleted":true,"size":1024  }];
var months = [,"JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","NOV","DEC"];
var re = /^(\d{4})-(\d{2})-(\d{2})/;
var results = data.reduce(function(results,value){
  var date = value.date.match(re);
  var temp = results;
  var key = date[1];
  if(!temp.hasOwnProperty(key)) temp[key] = {};
  temp = temp[key];
  key = months[date[2]|0];
  if(!temp.hasOwnProperty(key)) temp[key] = {};
  temp = temp[key];
  key = date[3];
  if(!temp.hasOwnProperty(key)) temp[key] = [];
  temp = temp[key];
  
  temp.push(value);
  return results;
},{});
console.log(results);

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Javascript对象组按天，月，年

2 个答案: