这是我在theano中的代码
max_max=200
beReplaced=T.matrix()
toReplace=T.matrix()
timeArray=T.arange(max_max)
def f(v,k,w):
return T.concatenate([w[:k],v,w[k+1:]],axis=0)
result,_=theano.scan(f,
sequences=[toReplace,timeArray],
outputs_info=beReplaced)
我要做的是逐行用beReplaced
替换toReplace
。我这样做的方法是concatenate
w
的上半部分,v
和lower
w
的上半部分。
v
是toReplace
的行。
以下是错误报告
Traceback (most recent call last):
File "/Users/qiansteven/Desktop/NLP/RNN/my.py", line 20, in <module>
outputs_info=np.zeros((5,5),dtype=np.float64))
File "/usr/local/lib/python2.7/site-packages/theano/scan_module/scan.py", line 745, in scan
condition, outputs, updates = scan_utils.get_updates_and_outputs(fn(*args))
File "/Users/qiansteven/Desktop/NLP/RNN/my.py", line 16, in f
return T.concatenate([a,b,c],axis=0)
File "/usr/local/lib/python2.7/site-packages/theano/tensor/basic.py", line 4225, in concatenate
return join(axis, *tensor_list)
File "/usr/local/lib/python2.7/site-packages/theano/gof/op.py", line 611, in __call__
node = self.make_node(*inputs, **kwargs)
File "/usr/local/lib/python2.7/site-packages/theano/tensor/basic.py", line 3750, in make_node
axis, tensors, as_tensor_variable_args, output_maker)
File "/usr/local/lib/python2.7/site-packages/theano/tensor/basic.py", line 3816, in _make_node_internal
raise TypeError("Join() can only join tensors with the same "
TypeError: Join() can only join tensors with the same number of dimensions.
出了什么问题????????????
答案 0 :(得分:0)
将toReplace
放入non_sequences
,否则每个时间步只会占用一部分。当尝试将向量与矩阵连接时,Theano将报告错误。
def f(k,w,v): #NOTE the argument order change
return T.concatenate([w[:k],v,w[k+1:]],axis=0)
result,_=theano.scan(f,
sequences=timeArray,
outputs_info=beReplaced,
non_sequences=toReplace)