Question

如何在用户输入正确的号码后更改随机数？我试过了，但似乎如果我使用while，数字总是正确的，所以它会产生无限循环

    final TextView randomnumber = (TextView) findViewById(R.id.randomTextView);
    final EditText number = (EditText) findViewById(R.id.editText2);
    final EditText number2 = (EditText) findViewById(R.id.editText);
    final EditText yourchoose = (EditText) findViewById(R.id.choose);
    Button button = (Button) findViewById(R.id.button);
    button.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            int a = Integer.parseInt(number.getText().toString());
            int b = Integer.parseInt(number2.getText().toString());
            int d = (int) (Math.random() * (a - b) + b);
            int c = Integer.parseInt(yourchoose.getText().toString());
            if(d > c) {
                randomnumber.setText("Choose Bigger");
            } else if (d < c) {
                randomnumber.setText("Choose Smaller");
            } else {
                randomnumber.setText("You're Right, The number is " + d);
            }
        }
    });

Answer 1

在onClick之外生成一个随机数。从while中删除onClick循环。请参阅下面的代码，

final TextView randomnumber = (TextView) findViewById(R.id.randomTextView);
final EditText number = (EditText) findViewById(R.id.editText2);
final EditText number2 = (EditText) findViewById(R.id.editText);
final EditText yourchoose = (EditText) findViewById(R.id.choose);

Random rand = new Random();
final int randomNumber = rand.nextInt();

Button button = (Button) findViewById(R.id.button);
button.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {
        int a = Integer.parseInt(number.getText().toString());
        int b = Integer.parseInt(number2.getText().toString());
        int c = Integer.parseInt(yourchoose.getText().toString());

        int random = (int) (randomNumber * (a - b) + b);
        if (random > c) {
            randomnumber.setText("Choose Bigger");
        } else if (random < c) {
            randomnumber.setText("Choose Smaller");
        } else {
            randomnumber.setText("Your're Right, Number is " + random);
        }

    }
});

修改

再次看一下，生成的随机数应该在以下范围之间

b＆lt; randomNumber＆lt; （a - b）

所以我使用TextWatcher收听number和number2 EditText上的chnage。

// Before onCreate int a = 0, b = 0, c, random = 0; //inside onCreate final TextView randomnumber = (TextView) findViewById(R.id.randomTextView); final EditText number = (EditText) findViewById(R.id.editText2); final EditText number2 = (EditText) findViewById(R.id.editText); final EditText yourchoose = (EditText) findViewById(R.id.choose); final Random rand = new Random(); number.addTextChangedListener(new TextWatcher() { @Override public void afterTextChanged(Editable s) { a = Integer.parseInt(number.getText().toString()); random = rand.nextInt(a - b) + b; } @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) {} @Override public void onTextChanged(CharSequence s, int start, int count, int after){} }); number2.addTextChangedListener(new TextWatcher() { @Override public void afterTextChanged(Editable s) { b = Integer.parseInt(number2.getText().toString()); random = rand.nextInt(a - b) + b; } @Override public void beforeTextChanged(CharSequence s, int start, int count, int after) {} @Override public void onTextChanged(CharSequence s, int start, int count, int after){} }); Button button = (Button) findViewById(R.id.button); button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { int c = Integer.parseInt(yourchoose.getText().toString()); if (random > c) { randomnumber.setText("Choose Bigger"); } else if (random < c) { randomnumber.setText("Choose Smaller"); } else { randomnumber.setText("Your're Right, Number is " + random); } } });

Answer 2

因为c和random的值在while循环中没有变化，所以它继续。

例如：如果random的值为5且c为3.一旦进入循环，值保持不变，而（random！= c）始终为true，因此它不会停止。

用户获得正确的号码后如何更改随机数？

2 个答案: