Question

我正在尝试更改应用启动时生成的随机数，并要求用户输入新内容？如您所见，当前代码显示如果用户猜出正确的数字，他将不得不再次重启应用程序。而不是这样做，我想在客户正确的时候继续改变随机数。

public class MainActivity extends Activity {

int randomNumber;
int number;

public void randomNumberGenerator (View view){
    EditText userInput = (EditText)findViewById(R.id.userRandomText);
    do {
        number = Integer.parseInt(userInput.getText().toString());

        if (number == randomNumber) {
            Toast.makeText(getApplicationContext(), "Your number " + number + "is equal to generated number. CONGRATULATION !! Try Again: ", Toast.LENGTH_SHORT).show();
        } else if (number < randomNumber) {
            Toast.makeText(getApplicationContext(), "Your number " + number + "is lower than generated random number", Toast.LENGTH_SHORT).show();
        } else {
            Toast.makeText(getApplicationContext(), "Your number " + number + "is greater than generated random number", Toast.LENGTH_SHORT).show();
        }
          };

  @Override
   protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main_activity_udemy);
    //Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar);
    //setSupportActionBar(toolbar);

    Random randomGenerator = new Random();
    randomNumber = randomGenerator.nextInt(20);
    System.out.print(randomNumber);

Answer 1

将这些行移至generateRandomNumber

Random randomGenerator = new Random();
randomNumber = randomGenerator.nextInt(20);
System.out.print(randomNumber);

然后你可以在用户猜对了

时再添加一次

randomNumber = randomGenerator.nextInt(20);

所以你的代码看起来像这样

Random randomGenerator = new Random();
randomNumber = randomGenerator.nextInt(20);
System.out.print(randomNumber);
do {
    number = Integer.parseInt(userInput.getText().toString());
    if (number == randomNumber) {
        Toast.makeText(getApplicationContext(), "Your number " + number + "is equal to generated number. CONGRATULATION !! Try Again: ", Toast.LENGTH_SHORT).show();
        randomNumber = randomGenerator.nextInt(20);
    } else if (number < randomNumber) {
        Toast.makeText(getApplicationContext(), "Your number " + number + "is lower than generated random number", Toast.LENGTH_SHORT).show();
    } else {
        Toast.makeText(getApplicationContext(), "Your number " + number + "is greater than generated random number", Toast.LENGTH_SHORT).show();
    }
}

Android猜数字游戏？如何在用户正确使用时更改随机数？

1 个答案: