我正在尝试使用具有不同x
组的seaborn和其他hues
来生成箱线图。看到这段代码:
tips = sns.load_dataset("tips")
sns.stripplot(x="day", y="total_bill", hue="smoker",
data=tips, jitter=True,
palette="Set2", split=True,linewidth=1,edgecolor='gray')
sns.boxplot(x="day", y="total_bill", hue="smoker",
data=tips,palette="Set2",fliersize=0)
我希望每个x
箱形图(在这个例子中,每天)都是不同的颜色,而每个hue
(在这种情况下,吸烟者/非吸烟者)用在swarmplot上有一个不同的符号。
我试图使用palette
参数,但没有得到我想要的。我还尝试直接使用artists
,但更改框图的facecolor
也会因某种原因更改edgecolor
,我不知道如何更改无论如何,swarmplot。
答案 0 :(得分:1)
when answering this question我意识到,即使我前一阵子也曾一起砍过东西,但从未提出过自己的解决方案。
# From itertools' receipes https://docs.python.org/3/library/itertools.html#itertools-recipes
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)
fig, ax = plt.subplots()
# dummy plots, just to get the Path objects
a = ax.scatter([1,2],[3,4], marker='s')
b = ax.scatter([1,2],[3,4], marker='^')
square_mk, = a.get_paths()
triangle_up_mk, = b.get_paths()
a.remove()
b.remove()
sns.swarmplot(x="day", y="total_bill", hue="smoker", data=tips, dodge=True, size=6, lw=2, edgecolor='k')
swarm_cols = ax.collections
sns.boxplot(x="day", y="total_bill", hue="smoker", data=tips, fliersize=0)
box_cols = ax.artists
ax.legend_.remove()
N_cats = len(np.unique(tips.day))
N_hues = len(np.unique(tips.smoker))
print(N_cats,N_hues)
pastels = matplotlib.cm.get_cmap('Pastel1')
cat_colors = [pastels(x) for x in np.linspace(0,1,N_cats)]
hue_markers = [square_mk, triangle_up_mk]
for boxes,color in zip(grouper(box_cols, N_hues),cat_colors):
for box in boxes:
box.set_facecolor(color)
for swarms,color in zip(grouper(swarm_cols, N_hues), cat_colors):
for swarm,marker in zip(swarms,hue_markers):
print(swarm, len(swarm.get_offsets()))
swarm.set_paths([marker])
swarm.set_facecolors([color])
swarm.set_linewidths([1.])
swarm.set_edgecolors(['xkcd:dark grey'])
# recreate legend
for swarm,marker in zip(swarm_cols[-2:],hue_markers):
print(swarm, len(swarm.get_offsets()))
swarm.set_paths([marker])
swarm.set_facecolors(["none"])
swarm.set_linewidths([1.])
swarm.set_edgecolors(['xkcd:dark grey'])
ax.legend(swarm_cols[-2:],np.unique(tips.smoker))
答案 1 :(得分:0)
对于问题的着色部分:edgecolor和facecolor都可以通过艺术家单独指定。
ax = sns.boxplot(x="day", y="total_bill", hue="smoker",
data=tips,fliersize=0)
colors = sns.color_palette('husl',n_colors=4)
colors = sp.repeat(colors,2,axis=0)
for artist,color in zip(ax.artists,colors):
artist.set_facecolor(color)
artist.set_edgecolor(color)
对于stripplot:我也找不到如何机会制造者的方法。如果你想指定它们的颜色等,你可以通过[pc for pc in ax.get_children() if type(pc) == PathCollection]
单独获取它们......