Question

我正在使用x86程序集，并且使用它，我需要使用20个字符或更多字符串，并从用户获取一个字符。然后我需要将每个字符串旋转两位，然后使用ASCII代码XOR。

问题是我可以获取用户字符串和char，但是如何循环遍历字符串？我尝试像数组一样循环遍历它，但随后它就崩溃了。

.386
.model flat,stdcall
.stack 4096
  ExitProcess proto,dwExitCode:dword
  WriteDec PROTO
  WriteString PROTO
  WriteChar PROTO
  Crlf PROTO
  ReadString PROTO
  DumpRegs PROTO
  Delay PROTO
.data
  MAX = 80                        ;max chars to read, if we input more it just gets cut off
  stringIn BYTE MAX+1 DUP (?)     ;room for null
  stringASCII BYTE MAX+1 DUP (?)  ;room for null
  CharMAX = 2;
  storedString DWORD ?
  storedASCII  DWord ?
  savedSpots   Dword ?

  Command      byte  "Enter your 20 Word string"  ,0
  askforChar   byte  "Enter a char"  ,0
  Encrypt      byte  "Encrypted String"  ,0


.code
main PROC
  mov  edx , OFFSET Command     ;Enter your 20 word String
  call WriteString              ;print it
  call CRLF                     ;space
  mov  edx, OFFSET stringIn     ;get the address of where we are gonna put our response
  mov  ecx, MAX                 ;mov max value of chars
  call ReadString               ;read it
  call CRLF                     ;space

  mov  edx , OFFSET askforChar  ;Then ask for a single char
  call WriteString              ;write it out
  call CRLF                     ;clear the line
  mov  edx, OFFSET stringASCII  ;get the address of where we are gonna put our char
  mov  ecx, CharMAX             ;get the one ASCII code
  call ReadString               ;double space
  call CRLf                     ;double space

  mov  edx, OFFSET stringASCII  ;this was just a test to reprint our word
  mov  storedASCII, edx         ;
  mov  ecx, CharMAX             ;get the same max value
  call CRLF

  mov  edx , OFFSET Encrypt     ;Encrypted String
  call WriteString              ;print it
  call CRLF                     ;space
  mov  esi,OFFSET stringIN      ;get our string address
  mov  ecx, MAX                 ;get our counter
L1:
  mov  edx, [esi]
  call WriteChar
  call CRLF
  add  esi, TYPE stringIN
Loop L1;
  ret
main ENDP
end main

编辑：重新添加循环

汇编Irvine x86使用ASCII加密和解密

0 个答案: