我正在尝试使用存储在名为“jsonFieldName”的变量中的值的位置从JSON数组响应中提取名称值“Acura”。
下面是我尝试使用的代码,但是,每次运行脚本时,SOAPUI都会返回错误:“java.lang.NullPointerException:无法在null对象上获取属性'name'错误:156 “
有人可以建议如何做到这一点吗?
import groovy.json.JsonSlurper
def response = '''{
"makes": [
{
"id": 200002038,
"name": "Acura",
"niceName": "acura",
"models": [
{
"id": "Acura_ILX",
"name": "ILX",
"niceName": "ilx",
"years": [
{
"id": 200471908,
"year": 2014
}
]
},
{
"id": "Acura_ILX_Hybrid",
"name": "ILX Hybrid",
"niceName": "ilx-hybrid",
"years": [
{
"id": 200493809,
"year": 2014
}
]
},
{
"id": "Acura_MDX",
"name": "MDX",
"niceName": "mdx",
"years": [
{
"id": 200465929,
"year": 2014
}
]
},
{
"id": "Acura_RDX",
"name": "RDX",
"niceName": "rdx",
"years": [
{
"id": 200467168,
"year": 2014
}
]
},
{
"id": "Acura_RLX",
"name": "RLX",
"niceName": "rlx",
"years": [
{
"id": 100539511,
"year": 2014
}
]
},
{
"id": "Acura_TL",
"name": "TL",
"niceName": "tl",
"years": [
{
"id": 200488448,
"year": 2014
}
]
},
{
"id": "Acura_TSX",
"name": "TSX",
"niceName": "tsx",
"years": [
{
"id": 200490517,
"year": 2014
}
]
},
{
"id": "Acura_TSX_Sport_Wagon",
"name": "TSX Sport Wagon",
"niceName": "tsx-sport-wagon",
"years": [
{
"id": 200673755,
"year": 2014
}
]
}
]
},
{
"id": 200001769,
"name": "Aston Martin",
"niceName": "aston-martin",
"models": [
{
"id": "Aston_Martin_DB9",
"name": "DB9",
"niceName": "db9",
"years": [
{
"id": 200473436,
"year": 2014
}
]
},
{
"id": "Aston_Martin_Rapide_S",
"name": "Rapide S",
"niceName": "rapide-s",
"years": [
{
"id": 200460643,
"year": 2014
}
]
},
{
"id": "Aston_Martin_V8_Vantage",
"name": "V8 Vantage",
"niceName": "v8-vantage",
"years": [
{
"id": 200472947,
"year": 2014
}
]
},
{
"id": "Aston_Martin_Vanquish",
"name": "Vanquish",
"niceName": "vanquish",
"years": [
{
"id": 200431313,
"year": 2014
}
]
}
]
}
],
"makesCount": 2
}'''
def jsonFieldName = ('makes[0].name')
def json = new JsonSlurper().parseText (response)
jsonFieldName.split("\\.").each{json = json[it]}
assert json == 'Acura'
答案 0 :(得分:0)
假设您的JSON响应良好(通过致电print
查看),请尝试将.text
添加到jsonSlurper()
来电
您似乎在parseText
和(response)
之间有空格
所以它应该是
def json = new JsonSlurper().parseText(response)
但是我会尝试转换为ArrayList<LazyMap>
,以确保您可以通过执行迭代
ArrayList<LazyMap> json = new JsonSlurper().parseText(response) as ArrayList<LazyMap>
然后致电:
json.get('Acura')
答案 1 :(得分:0)
这行代码不能处理索引解析:
jsonFieldName.split("\\.").each{json = json[it]}
没有名称为makes[0]
的密钥。相反,有一个makes
数组,你对第一个感兴趣。以下硬编码行检索name属性:
def result = json.'makes'[0].'name'
正如您在此处所看到的,还有一个步骤来解决索引运算符。当然,您可以自己实现此功能,也可以使用JsonPath代替JsonSlurper
。
答案 2 :(得分:0)
好的,所以我设法通过使用JsonPath而不是JsonSlurper来实现这一点。
为实现这一目标,我必须导入以下内容:
导入com.jayway.jsonpath.JsonPath
def jsonFieldName = "makes[0].name"
def expectedValue = "Acura"
def jsonSuff = JsonPath.read(response, jsonFieldName)
log.info(jsonSuff)
if (jsonSuff.toString() == expectedValue.toString()){
log.info("Actual value"+jsonSuff+"is equal to expected value"+expectedValue)
}