这是我试图解析的JSON响应:
{
"data": {
"Content": {
"id": 26,
"name": "Dashboard1"
},
"List": [
{
"ListContent": {
"id": 178,
"name": "Card-144"
},
"cards": [
{
"id": 1780,
"configuration": {
"id": 7178,
"name": "Emp"
}
}
]
},
{
"ListContent": {
"id": 179,
"name": "Card-14"
},
"cards": [
{
"id": 1798,
"configuration": {
"id": 1789,
"name": "RandomColumns"
}
}
]
},
{
"ListContent": {
"id": 180,
"name": "Card-1"
},
"cards": [
{
"id": 18080,
"configuration": {
"id": 1080,
"allow": true
}
}
]
},
{
"ListContent": {
"id": 181,
"name": "Card-14"
},
"cards": [
{
"id": 18081,
"configuration": {
"id": 1881,
"name": "Functions"
}
}
]
},
{
"ListContent": {
"id": 182,
"name": "Card-1443"
},
"cards": [
{
"id": 1782,
"configuration": {
"id": 1802,
"name": "Emp-O"
}
}
]
}
]
}
}
从Json,我需要在" ListContent"下提取" id"节点并将其存储在一个数组中。此外,还需要忽略子节点下的" id" s。 这是一个groovy脚本,我试图实现这一点,
def CList = ""
import groovy.json.JsonSlurper
def jsonRespData = context.expand( '${TestStep#Response#$.data.List}' )
def outputResp = new JsonSlurper().parseText(jsonRespData)
outputResp.id.each()
{log.info( ":"+ it)
CList=CList.concat(it.toString()).concat(',')}
log.info (CList)
所以,我期待的数组是CList [178,179,180,181,182] 但我目前无效。 什么应该是正确的groovy只能阅读" id"来自" ListContent"并将其写入数组? 任何帮助将非常感激。 提前谢谢。
答案 0 :(得分:1)
def str = '''
{
"data": {
"Content": {
"id": 26,
"name": "Dashboard1"
},
"List": [
{
"ListContent": {
"id": 178,
"name": "Card-144"
},
"cards": [
{
"id": 1780,
"configuration": {
"id": 7178,
"name": "Emp"
}
}
]
},
{
"ListContent": {
"id": 179,
"name": "Card-14"
},
"cards": [
{
"id": 1798,
"configuration": {
"id": 1789,
"name": "RandomColumns"
}
}
]
},
{
"ListContent": {
"id": 180,
"name": "Card-1"
},
"cards": [
{
"id": 18080,
"configuration": {
"id": 1080,
"allow": true
}
}
]
},
{
"ListContent": {
"id": 181,
"name": "Card-14"
},
"cards": [
{
"id": 18081,
"configuration": {
"id": 1881,
"name": "Functions"
}
}
]
},
{
"ListContent": {
"id": 182,
"name": "Card-1443"
},
"cards": [
{
"id": 1782,
"configuration": {
"id": 1802,
"name": "Emp-O"
}
}
]
}
]
}
}
'''
def outputResp = new groovy.json.JsonSlurper().parseText(str)
outputResp.data.List.collect { it.ListContent.id }
正如您已经从List
获得context.expand( '${TestStep#Response#$.data.List}' )
,您可以这样做:
outputResp.collect { it.ListContent.id }
上方返回ArrayList
。
答案 1 :(得分:1)
你可以像这样使用(隐式)扩展运算符:
def json = new groovy.json.JsonSlurper().parse('/tmp/x.json' as File)
//
def i = json.data.List.ListContent.id
assert i == [178, 179, 180, 181, 182]
// with explicit spread operator
def e = json.data.List*.ListContent*.id
assert e == [178, 179, 180, 181, 182]