我试图提取自行车品牌" Cannondale"从JSON响应中使用存储在名为" jsonFieldName"
的变量中的值的位置或者,我可以使用以下语法成功提取品牌价值:
def response = ('''{
"store": {
"book": [
{
"title": "Sword of Honour",
"category": "fiction",
"author": "Evelyn Waugh",
"@price": 12.99
},
{
"title": "Moby Dick",
"category": "fiction",
"author": "Herman Melville",
"isbn": "0-553-21311-3",
"@price": 8.99
},
{
"title": "Sayings of the Century",
"category": "reference",
"author": "Nigel Rees",
"@price": 8.95
},
{
"title": "The Lord of the Rings",
"category": "fiction",
"author": "J. R. R. Tolkien",
"isbn": "0-395-19395-8",
"@price": 22.99
}
],
"bicycle": {
"brand": "Cannondale",
"color": "red",
"price": 19.95
}
}
}''').toString()
//store location of json property I want to extract in property called jsonFieldName
def jsonFieldName = "store.bicycle.brand"
def json = new JsonSlurper().parseText (response)
//perform extraction
brand = json."${jsonFieldName}"
但是,我想将元素的位置保存在变量中。原因是,我希望能够在Json Response上迭代多个断言,作为我的自动化套件的一部分。
有人可以建议怎么做吗?
以下是我目前在变量中存储位置的代码段。但它不起作用,总是将品牌归还为“Null' :( 感谢。
{{1}}
答案 0 :(得分:3)
new JsonSlurper().parseText(response)
会返回map,因此,搜索"store.bicycle.brand"
会在store.bicycle.brand
变量中查找名为json
的密钥,而您希望查看首先在json['store']
中,然后在索引['bicycle']
中,依此类推。
我使用inject
策略来做你想做的事:
def response = '''{
"store": {
"bicycle": {
"brand": "Cannondale",
"color": "red",
"price": 19.95
}
}
}'''
def jsonFieldName = "store.bicycle.brand"
def json = new groovy.json.JsonSlurper().parseText (response)
get = { field, json2 ->
field.tokenize(".").inject(json2) { map, f -> map[f] }
}
brand = get jsonFieldName, json
assert brand == 'Cannondale'
答案 1 :(得分:0)
问题是使用字符串访问属性;该字符串被视为属性的全名,因此您无法使用它来访问多个深度属性;换句话说,const QString getData();
被视为属性名称的一部分。
可能的解决方法是将字符串拆分为.
字符并逐个访问属性:
.