我使用Caffe训练了我的数据。以下是solver.prototxt文件中的参数。
test_iter: 100
test_interval: 1000
base_lr: 0.00001
lr_policy: "step"
gamma: 0.1
stepsize: 20000
display: 20
max_iter: 13000
momentum: 0.9
weight_decay: 0.0005
snapshot: 10000
solver_mode: GPU
测试精度约为0.0185，第一次测试时测试损失约为2.85。 在13000处，测试精度为0.92，测试损失为0.52。 我如何评估准确性是好还是过度拟合数据？我可以使用任何方法进行评估吗？ 以下是每次测试的准确度和损耗。
I1031 11:36:47.063542 18188 solver.cpp:404] Test net output #0: accuracy = 0.0184
I1031 11:36:47.063623 18188 solver.cpp:404] Test net output #1: loss = 2.85812 (* 1 = 2.85812 loss)
I1031 11:38:49.832749 18188 solver.cpp:337] Iteration 1000, Testing net (#0)
I1031 11:38:55.510437 18188 solver.cpp:404] Test net output #0: accuracy = 0.764
I1031 11:38:55.510509 18188 solver.cpp:404] Test net output #1: loss = 1.1725 (* 1 = 1.1725 loss)
I1031 11:40:59.547670 18188 solver.cpp:337] Iteration 2000, Testing net (#0)
I1031 11:41:04.451655 18188 solver.cpp:404] Test net output #0: accuracy = 0.6372
I1031 11:41:04.451717 18188 solver.cpp:404] Test net output #1: loss = 1.44847 (* 1 = 1.44847 loss)
I1031 11:43:05.340741 18188 solver.cpp:337] Iteration 3000, Testing net (#0)
I1031 11:43:09.262504 18188 solver.cpp:404] Test net output #0: accuracy = 0.8844
I1031 11:43:09.262568 18188 solver.cpp:404] Test net output #1: loss = 0.576498 (* 1 = 0.576498 loss)
I1031 11:45:10.821233 18188 solver.cpp:337] Iteration 4000, Testing net (#0)
I1031 11:45:14.686005 18188 solver.cpp:404] Test net output #0: accuracy = 0.5484
I1031 11:45:14.686064 18188 solver.cpp:404] Test net output #1: loss = 1.91799 (* 1 = 1.91799 loss)
I1031 11:47:17.107151 18188 solver.cpp:337] Iteration 5000, Testing net (#0)
I1031 11:47:21.160307 18188 solver.cpp:404] Test net output #0: accuracy = 0.8908
I1031 11:47:21.160372 18188 solver.cpp:404] Test net output #1: loss = 0.54212 (* 1 = 0.54212 loss)
I1031 11:49:23.325654 18188 solver.cpp:337] Iteration 6000, Testing net (#0)
I1031 11:49:27.229637 18188 solver.cpp:404] Test net output #0: accuracy = 0.7384
I1031 11:49:27.229677 18188 solver.cpp:404] Test net output #1: loss = 1.1355 (* 1 = 1.1355 loss)
I1031 11:51:29.619175 18188 solver.cpp:337] Iteration 7000, Testing net (#0)
I1031 11:51:33.568794 18188 solver.cpp:404] Test net output #0: accuracy = 0.6264
I1031 11:51:33.568837 18188 solver.cpp:404] Test net output #1: loss = 1.10095 (* 1 = 1.10095 loss)
I1031 11:53:36.075034 18188 solver.cpp:337] Iteration 8000, Testing net (#0)
I1031 11:53:39.969431 18188 solver.cpp:404] Test net output #0: accuracy = 0.9156
I1031 11:53:39.969481 18188 solver.cpp:404] Test net output #1: loss = 0.522906 (* 1 = 0.522906 loss)
I1031 11:55:42.594107 18188 solver.cpp:337] Iteration 9000, Testing net (#0)
I1031 11:55:46.473902 18188 solver.cpp:404] Test net output #0: accuracy = 0.5228
I1031 11:55:46.473961 18188 solver.cpp:404] Test net output #1: loss = 1.63102 (* 1 = 1.63102 loss)
I1031 11:57:55.669351 18188 solver.cpp:337] Iteration 10000, Testing net (#0)
I1031 11:57:59.571413 18188 solver.cpp:404] Test net output #0: accuracy = 0.8472
I1031 11:57:59.571485 18188 solver.cpp:404] Test net output #1: loss = 0.638568 (* 1 = 0.638568 loss
I1031 12:00:01.984112 18188 solver.cpp:337] Iteration 11000, Testing net (#0)
I1031 12:00:05.870985 18188 solver.cpp:404] Test net output #0: accuracy = 0.7476
I1031 12:00:05.871040 18188 solver.cpp:404] Test net output #1: loss = 1.19568 (* 1 = 1.19568 loss)
I1031 12:02:08.464495 18188 solver.cpp:337] Iteration 12000, Testing net (#0)
I1031 12:02:12.397044 18188 solver.cpp:404] Test net output #0: accuracy = 0.596
I1031 12:02:12.397104 18188 solver.cpp:404] Test net output #1: loss = 1.32557 (* 1 = 1.32557 loss)
I1031 12:04:24.876971 18188 solver.cpp:337] Iteration 13000, Testing net (#0)
I1031 12:04:28.693732 18188 solver.cpp:404] Test net output #0: accuracy = 0.9284
I1031 12:04:28.693771 18188 solver.cpp:404] Test net output #1: loss = 0.521483 (* 1 = 0.521483 loss)
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答案 0 :(得分：0)
过度拟合是指训练精度的提高不会导致测试精度提高的情况。所以我建议你继续训练，直到发生这种情况，或者你对测试的准确性感到满意。