Question

我只是想点击网址，即www.google.com 我希望捕获整个json响应作为输出... 我尝试了多个代码，这些代码只能帮助我找到响应代码，但我想要完整的json响应，我可以从中过滤掉一些信息。

我正在为网络做的事情......

Answer 1

我使用了ApacheHttpClient jar（版本4.5.1）。你还需要HttpCore库（我使用4.4.3）和其他一些apache库（比如编解码器）。

以下是GET方法和POST方法：

public static String getJsonStringHttpGet(String url,Map<String,String> headers) throws IOException {

        BasicCookieStore cookieStore = new BasicCookieStore();

        CloseableHttpClient httpClient = HttpClients.custom()
                .setDefaultCookieStore(cookieStore)
        .build();

        HttpCoreContext localContext = new HttpCoreContext();


        HttpGet get = new HttpGet(url);


        /*
         * if you need to specify headers
         */
        if (headers != null) {
            for (String name : headers.keySet()) {
                get.addHeader(name, headers.get(name));
            }
        }



        HttpResponse response = httpClient.execute(get, localContext);



        byte [] bytes = EntityUtils.toByteArray(response.getEntity());


        return new String(bytes);

    }

public static String getJsonStringHttpPost(String url,Map<String,String> postParams,Map<String,String> headers) throws IOException {

        BasicCookieStore cookieStore = new BasicCookieStore();

        CloseableHttpClient httpClient = HttpClients.custom()
                .setDefaultCookieStore(cookieStore)
        .build();

        HttpCoreContext localContext = new HttpCoreContext();


        HttpPost post = new HttpPost(url);

        /*
         * adding some POST params
         */
        if (postParams != null && postParams.size() > 0) {

            List<BasicNameValuePair> postParameters = new ArrayList<>();

            for (String name : postParams.keySet()) {
                postParameters.add(new BasicNameValuePair(name, postParams.get(name)));
            }

            post.setEntity(new UrlEncodedFormEntity(postParameters));
        }

        /*
         * if you need to specify headers
         */
        if (headers != null) {
            for (String name : headers.keySet()) {
                post.addHeader(name, headers.get(name));
            }
        }



        HttpResponse response = httpClient.execute(post, localContext);



        byte [] bytes = EntityUtils.toByteArray(response.getEntity());


        return new String(bytes);

    }

然后你可以随意解析json字符串。

希望这有帮助

如何使用httprequest获取完整的json响应

1 个答案: