我遇到了Node.js http.get
的奇怪行为。我使用ajax向url发出请求,并希望将结果输入我的浏览器。但我只获得了一些<head>
标记内容,而不是<body>
内容。但是如果我将结果发送到系统控制台(console.log(chunk)
),我会得到我想要的结果 - 整页。以下是我的步骤:
// Simple jQuery Ajax GET
$.ajax({
type: "GET",
url: "/myapppath", // send to my app's url
data: {foo: "bar"},
success: onLoad, // the callback, see just bellow
error: onError,
dataType: "text"
});
// With this callback function I want to insert the result into <div id="baz">
function onLoad(resp) {
document.getElementById("baz").innnerHTML = resp;
}
// In /myapppath
http.get("http://stackoverflow.com/", function(result) {
result.setEncoding('utf8');
result.on("data", function(chunk) {
console.log(chunk); // this successfully returns the whole page but into system console
res.end(chunk); // this returns just a piece of <head> tag into the browser.
});
});
因此,在我的<div id="baz">
中,我只获得<head>
个http://stackoverflow.com/
个<body>
标记,<div id="baz">
标记及其内容。这就是我在<!DOCTYPE html>
<html>
<head>
<title>Stack Overflow</title>
<link rel="shortcut icon" href="https://cdn.sstatic.net/stackoverflow/img/favicon.ico">
<link rel="apple-touch-icon image_src" href="https://cdn.sstatic.net/stackoverflow/img/apple-touch-icon.png">
<link rel="search" type="application/opensearchdescription+xml" title="Stack Overflow" href="/opensearch.xml">
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript" src="https://cdn.sstatic.net/js/stub.js?v=dd6898efd655"></script>
<link rel="stylesheet" type="text/css" href="https://cdn.sstatic.net/stackoverflow/all.css?v=8a5907e853ab">
<link rel="alternate" type="application/atom+xml" title="Feed of recent questions" href="/feeds">
<script type="text/javascript" defer>
</script>
<script type="text/javascript"> StackExchange.init({"stackAuthUrl":"https://stackauth.com","serverTime":1374771485,"styleCode":true,"enableUserHovercards":true,"site":{"name":"Stack Overflow","description":"Q&A for professional and enthusiast programmers","isNoticesTabEnabled":true,"recaptchaPublicKey":"6LdchgIAAAAAAJwGpIzRQSOFaO0pU6s44Xt8aTwc","enableSocialMediaInSharePopup":true},"user":{"fkey":"b1d105a0cf61e49216c5750a6ad60dec","isAnonymous":true}});
StackExchange.using.setCacheBreakers({"js/prettify-full.js":"6c261bebf56a","js/moderator.js":"7cf00e91ce39","js/full-anon.js":"c5bf51314708","js/full.js":"02e9182c23d3","js/wmd.js":"2f79c03846d5","js/third-party/jquery.autocomplete.min.js":"e5f01e97f7c3","js/mobile.js":"e8e23ad37820","js/help.js":"6e6623243cf6","js/tageditor.js":"450c9e8426fc","js/tageditornew.js":"b6c68ad4c7dd","js/inline-tag-editing.js":"8e84e8a137f7","js/revisions.js":"7273bb714bba","js/review.js":"2b3ae123e376","js/tagsuggestions.js":"aa48ef6154df","js/post-validation.js":"bb996020492a","js/explore-qlist.js":"1c5bbd79b562","js/events.js":"37756ef3ba47"});
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<script type="text/javascript">
StackExchange.using("gps", function() {
StackExchange.gps.init(true);
});
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<script type="text/javascript">
StackExchange.ready(function () {
$('#nav-tour').click(function () {
StackExchange.using("gps", function() {
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</script>
</h
而不是整个页面中的所有内容:
console.log(chunk)
但是在http.get
中我按照上面的描述在控制台中打印整页。
发生了什么事?为什么{{1}}没有向浏览器返回完整响应?我错过了什么?什么削减了回应?
答案 0 :(得分:14)
console.log(chunk);
实际上并不会一次记录整个页面,但随着更多chunk
到达,它确实会记录每个'data'
。
res.end()
在第一次通话后成为无操作,因为它关闭了连接,所以只包括第一个chunk
。
chunk
'data'
res.end()
res.write()
等待'end'
到http.get("http://stackoverflow.com/", function (result) {
result.on('data', function (chunk) {
res.write(chunk);
});
result.on('end', function () {
res.end();
});
});
:
result
或者,因为res
是Stream.Readable(IncomingMessage
)而http.get('http://stackoverflow.com', function (result) {
result.pipe(res);
});
可能是Stream.Writable(猜测ServerResponse
),所以应该能够.pipe()
他们:
{{1}}
答案 1 :(得分:11)
您的数据事件多次触发,但您只能“结束”输出一次......您应该重构您的处理程序,如下所示......
// In /myapppath
http.get("http://stackoverflow.com/", function(result) {
var responseParts = [];
result.setEncoding('utf8');
result.on("data", function(chunk) {
//add this chunk to the output to send
responseParts.push(chunk);
});
result.on("end", function(){
//now send your complete response
res.end(responseParts.join(''));
});
});