我想使用wp-api插件为我的wordpress网站构建一个Android应用程序。我如何在Json中发送HttpRequest(GET)和recive响应?
答案 0 :(得分:28)
使用此功能从URL获取JSON。
public static JSONObject getJSONObjectFromURL(String urlString) throws IOException, JSONException {
HttpURLConnection urlConnection = null;
URL url = new URL(urlString);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setReadTimeout(10000 /* milliseconds */ );
urlConnection.setConnectTimeout(15000 /* milliseconds */ );
urlConnection.setDoOutput(true);
urlConnection.connect();
BufferedReader br = new BufferedReader(new InputStreamReader(url.openStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
String jsonString = sb.toString();
System.out.println("JSON: " + jsonString);
return new JSONObject(jsonString);
}
不要忘记在清单中添加Internet权限
<uses-permission android:name="android.permission.INTERNET" />
然后像这样使用它:
try{
JSONObject jsonObject = getJSONObjectFromURL(urlString);
//
// Parse your json here
//
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
答案 1 :(得分:13)
尝试以下代码从网址
获取jsonHttpClient httpclient = new DefaultHttpClient();
HttpGet httpget= new HttpGet(URL);
HttpResponse response = httpclient.execute(httpget);
if(response.getStatusLine().getStatusCode()==200){
String server_response = EntityUtils.toString(response.getEntity());
Log.i("Server response", server_response );
} else {
Log.i("Server response", "Failed to get server response" );
}
答案 2 :(得分:0)
try {
String line, newjson = "";
URL urls = new URL(url);
try (BufferedReader reader = new BufferedReader(new InputStreamReader(urls.openStream(), "UTF-8"))) {
while ((line = reader.readLine()) != null) {
newjson += line;
// System.out.println(line);
}
// System.out.println(newjson);
String json = newjson.toString();
JSONObject jObj = new JSONObject(json);
}
} catch (Exception e) {
e.printStackTrace();
}