Question

我必须创建一个仅接受时钟输入的VHDL序列，然后输出5个led序列see picture 我是否正确认为使用std_logic_vector然后我可以将每个矢量输出连接到单个LED以创建此序列或者我错过了解释std_logic_vector的使用？

我使用的代码是

library ieee;
use ieee.std_logic_1164.all;
use ieee.std_logic_unsigned.all;
use ieee.numeric_std.all; -- i have used this package as my CLK-CNT signal    counts in integer format rather than binary and i am performing an ADD sum of   the CLK_CNT


entity REG_LED is
 PORT(CLK:      IN  std_logic;              -- CLK input
     LEDS:      Out std_logic_vector (4 downto 0) ); -- initialise output
End REG_LED;

ARCHITECTURE behavioral OF REG_LED IS
SIGNAL CLK_CNT:     integer range 0 to 9:= 0; -- initailise comparison signal used for counting clock pulses.
 -- This signal will be used by the program to recognise where in the sequnce the program is and thus determine the next state required for the sequence.
BEGIN

    CLK_Process:    PROCESS (CLK)   -- begin the CLK_CNT Process
    BEGIN 

    if rising_edge(CLK) Then
        if CLK_CNT = 8 then 
            CLK_CNT <= 0; -- this resets the clock pulse count to 0
        else
            CLK_CNT <= CLK_CNT + 1 ; -- used to count each clock pulse upto the reset 
        End if;
-- this process has been kept seperate to the LED output process in order to isolate the event from the output process and limit the possiblities of errors         
    END IF;

    END PROCESS ;

    LED_PROCESS: Process (CLK_CNT) -- LED Outputs based on Temp count

    BEGIN -- begin the output sequence 

        Case CLK_CNT is 
-- i use a case statement to compare the value of the CLK_CNT signal and produce the required LEDS output 
-- this ensures the 
            When 0 =>
                LEDS <= "11111"; -- S0 when clock count is 0
            When 1 =>
                LEDS <= "00001"; -- S1 when clock count is 1
            When 2 =>       
                LEDS <= "00001"; -- S2 when clock count is 2
            When 3 =>
                LEDS <= "11111"; -- S3 when clock count is 3
            When 4 =>
                LEDS <= "00000"; -- S4 when clock count is 4
            When 5 =>
                LEDS <= "11111"; -- S5 when clock count is 5
            When 6 =>
                LEDS <= "00100"; -- S6 when clock count is 6
            When 7 =>
                LEDS <= "01010"; -- S7 when clock count is 7
            When 8 =>
                LEDS <= "10001"; -- S8 when clock count is 8 this is the final clock count state

            When others => 
                LEDS <= "11111"; -- Restart Sequence

        End Case;               

    End Process;
END behavioral;

我已经模拟了波形并按照序列的要求产生了5个输出，但是这个输出可以用来驱动5个不同的LED，还是只是一个5位字输出一个端口？我是VHDL的新手，所以任何帮助将不胜感激

Answer 1

您的代码看起来很好，如果您的模拟显示它的功能符合您的需要，那么您几乎可以去。

std_logic_vector实际上是一些电线（总线）。你必须考虑它的物理意义，因为这是你编程FPGA时真正发生的事情。所以，是的，您可以将总线拆分（或突破）为单独的线路。这可以这样做：

signal LED_LINE_0 : std_logic;
signal LED_LINE_1 : std_logic;
LED_LINE_0 <= LEDS(0);
LED_LINE_1 <= LEDS(1);

......等等。这一次撕掉一根电线。您也可以通过一次拆除多条线路将总线分成较小的总线。 e.g。

signal small_bus_1 : std_logic_vector(1 downto 0);
signal small_bus_2 : std_logic_vector(1 downto 0);
signal big_bus : std_logic_vector(3 downto 0);

small_bus_1 <= big_bus(3 downto 2);
small_bus_2 <= big_bus(1 downto 0);

然后，您可以在约束文件中写入（或使用FPGA品牌的IDE中的GUI）来指定FPGA上您希望将每个std_logic分配给哪个引脚（驱动器）你需要的LED。）

VHDL CLOCK SEQUENCE Q3

1 个答案: