Java Server,Unity C#Client正在冻结

时间:2016-10-17 15:18:18

标签: java c# unity3d server tcpclient

我正在构建一个Unity3D应该与之通信的Sphinx4 Java服务器。将Unity C#中的音频数据发送到Java服务器工作正常。收到的数据的语音识别也可以正常工作。当我尝试将数据从Java发送回C#时出现问题。

我目前的代码: JAVA

package main;

import java.io.InputStream;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
import edu.cmu.sphinx.api.Configuration;
import edu.cmu.sphinx.api.SpeechResult;
import edu.cmu.sphinx.api.StreamSpeechRecognizer;

public class SpeechRecognition {

private static StreamSpeechRecognizer recognizer;
private static Configuration configuration;

public static void main(String[] args)  {

    configuration = new Configuration();
    configuration.setAcousticModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us");
    configuration.setDictionaryPath("resource:/edu/cmu/sphinx/models/en-us/cmudict-en-us.dict");
    configuration.setLanguageModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us.lm.bin");

    try {
        recognizer = new StreamSpeechRecognizer(configuration);
        ServerSocket serverSocket = new ServerSocket(82);

        while (System.in.available() == 0) {
            Socket socket = serverSocket.accept();
            System.out.println("Client found");
            String recognized = RecognizeText(socket.getInputStream());

            System.out.println("sending now");
            PrintWriter out = new PrintWriter(socket.getOutputStream(), true);

            String json = recognized;
            out.print(json);
            out.flush();
            out.close();

            socket.close();
        }
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    System.out.println("Quitting...");
    serverSocket.close();   

}

private static String RecognizeText(InputStream stream) throws Exception {
    recognizer.startRecognition(stream);
    SpeechResult result;
    String resultString="";
    while ((result = recognizer.getResult()) != null) {
        resultString = result.getHypothesis();
        System.out.format("Hypothesis: %s\n", resultString);
    }
    recognizer.stopRecognition();
    return resultString;
}

}

现在我的C#代码是这样的:

void Start () {       
    dataPath = Application.dataPath;
    t = new Thread(Client);
    t.Start();
}

private void Client()
{
    String input;

    TcpClient tcpClient = new TcpClient("localhost", 82);
    NetworkStream networkStream = tcpClient.GetStream();
    BinaryWriter bw = new BinaryWriter(networkStream);

    var filepath = dataPath + "/Resources/audio/test.wav";
    FileStream filestream = new FileStream(filepath, FileMode.Open, FileAccess.Read);
    BinaryReader filereader = new BinaryReader(filestream);
    byte[] bytes = filereader.ReadBytes((Int32)filestream.Length);
    bw.Write(bytes);
    bw.Flush();

    StreamReader streamReader = new StreamReader(networkStream);
    input = streamReader.ReadToEnd();
    print("Received data: " + input + "\n");
}

识别大约需要10秒钟。当给出结果时,系统冻结。 不打印Println(“立即发送”)(Java中)。所以它甚至在它到达之前就冻结了。

奇怪的是:当我只将文本从Java发送到C#或从C#发送到Java时,它可以工作。如果我想在两端发送和接收,它会冻结。我需要同时发送和接收数据

1 个答案:

答案 0 :(得分:0)

我找到了anwser: 在RecognizeText中没有中断循环,将while语句放在while循环中可以解决问题,因为无论如何都会首先返回识别的文本。