Question

我在表格中有传感器数据：

Time      Value
10        100
20        200
36        330
46        440

我想提取每个时间段的值变化。理想情况下，我想得到：

Starttime Endtime   Change
10        20        100
20        36        130
36        46        110

我的SQL技能非常简陋，所以我倾向于将所有数据输出到处理它的脚本，然后将其推回到新表中，但我想我会问是否有一个光滑的方式在数据库中完成所有操作。

Answer 1

Select a.Time as StartTime, b.time as EndTime, b.time-a.time as TimeChange, b.value-a.value as ValueChange
FROM YourTable a, YourTable b
WHERE b.time = (Select MIN(c.time) FROM YourTable c WHERE c.time>a.time)

Answer 2

Select a.Time as StartTime
     , b.time as EndTime
     , b.time-a.time as TimeChange
     , b.value-a.value as ValueChange
FROM YourTable a 
Left outer Join YourTable b ON b.time>a.time
Left outer Join YourTable c ON c.time<b.time AND c.time > a.time
Where c.time is null
Order By a.time

Answer 3

您可以使用SQL窗口函数，以下是基于BIGQUERY语法的示例。

SELECT 
  LAG(time, 1) OVER (BY time) AS start_time,
  time AS end_time, 
  (value - LAG(value, 1) OVER (BY time))/value AS Change
from data

Answer 4

首先，我会在表格中添加一个id列，以便您可以预测某些行从一行到另一行。

然后，我会尝试以下查询：

SELECT t1.Time AS 'Starttime', t2.Time AS 'Endtime',
    (t2.Value - t1.Value) AS 'Change'
FROM SensorData t1
INNER JOIN SensorData t2 ON (t2.id - 1) = t1.id
ORDER BY t1.Time ASC

我打算创建一个测试表来为自己尝试这个，所以我不知道它是否有效但是值得一试！

<强>更新修复了一个小问题（CHANGE是一个受保护的单词，必须引用）但测试它，它的工作原理！它完全产生上面定义的结果。

Answer 5

这有用吗？

WITH T AS
(
SELECT [Time]
    ,  Value
    ,  RN1 =  ROW_NUMBER() OVER (ORDER BY [Time])
    ,  RN2 =  ROW_NUMBER() OVER (ORDER BY [Time]) - 1   
FROM  SensorData
)
SELECT  
   StartTime = ISNULL(t1.[time], t2.[time])
 , EndTime = ISNULL(t2.[time], 0)
 , Change = t2.value - t1.value

FROM    T t1 
    LEFT OUTER JOIN 
        T t2

ON t1.RN1 = t2.RN2

SQL中的离散导数

5 个答案: