T-SQL中的拆分功能

时间:2016-10-04 11:34:28

标签: sql sql-server tsql split

我的表格包含以逗号分隔的字符串。我想创建返回以下结果的查询:

我想创建返回拆分文本的查询。对于exapmle:

表格中的数据:

| ID                                   | Names                            |
| ------------------------------------ | -------------------------------- |
| 63F5D993-3AC9-4EEA-8007-B669542BAD9A | John Smith,Kerry King,Tom Arraya |

必填结果:

 ID                                   | Names                             
------------------------------------  | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | John Smith                       
------------------------------------- | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | Kerry King                       
------------------------------------- | -----------
63F5D993-3AC9-4EEA-8007-B669542BAD9A  | Tom Arraya  

我发现"分裂" T-SQL的功能,但它的工作不太适合我的情况。我不能这样执行它:

SELECT dbo.Split(dbo.name, ',') FROM dbo.Mytable

它只能执行以下内容:

SELECT * FROM dbo.Split('John Smith,Kerry King,Tom Arraya', ',')

但它不适合我。 我也试图写光标:

DECLARE @bkb varchar(256)
DECLARE @Bkb_Cursor CURSOR 
SET @Bkb_Cursor = CURSOR SCROLL FOR  
SELECT bkb.best_know_by
  FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
  left JOIN [dbo].[email_addr_bean_rel]  eb
  ON eb.[bean_id] = c.[id]
  JOIN [dbo].[email_addresses] ea
  ON ea.[id] = eb.[email_address_id]
  JOIN [dbo].[contacts_cstm] ccs
  ON eb.bean_id = ccs.id_c
  left JOIN [dbo].[BestKnowBy$] bkb
  ON c.[campaign_id] =bkb.Con_id
  where c.deleted = 0;  
OPEN @Bkb_Cursor;  
FETCH NEXT FROM @Bkb_Cursor
INTO @bkb;
WHILE @@FETCH_STATUS = 0
BEGIN  
      PRINT dbo.Splitfn(@bkb);
      FETCH NEXT FROM @Bkb_Cursor INTO @bkb;  
END
CLOSE @Bkb_Cursor;  
DEALLOCATE @Bkb_Cursor;  
GO

但它没有奏效。我收到错误"专栏" dbo"在此上下文中不允许使用用户定义的函数或聚合" dbo.Splitfn"无法找到。"

我该如何解决这个问题?

我的查询如下:

SELECT c.[id], 
       bkb.best_know_by
  FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
  left JOIN [dbo].[email_addr_bean_rel]  eb
  ON eb.[bean_id] = c.[id]
  JOIN [dbo].[email_addresses] ea
  ON ea.[id] = eb.[email_address_id]
  JOIN [dbo].[contacts_cstm] ccs
  ON eb.bean_id = ccs.id_c
  left JOIN [dbo].[BestKnowBy$] bkb
  ON c.[campaign_id] =bkb.Con_id
  where c.deleted = 0; 

bkb.best_know_by字段包含逗号分隔的字符串。我如何使用" Cross Apply"在这种情况下?

2 个答案:

答案 0 :(得分:3)

您需要将CROSS APPLY与表格的结果集结合使用,该结果集将为每一行执行该功能:

SELECT st.ID, spl.value
FROM SplitTest st
CROSS APPLY string_split(st.Names, ',') spl

results

修改 关于在问题中添加查询,您可以执行以下操作:

;WITH CTE_Query AS (
    SELECT c.[id], 
       bkb.best_know_by
    FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
    left JOIN [dbo].[email_addr_bean_rel]  eb
    ON eb.[bean_id] = c.[id]
    JOIN [dbo].[email_addresses] ea
    ON ea.[id] = eb.[email_address_id]
    JOIN [dbo].[contacts_cstm] ccs
    ON eb.bean_id = ccs.id_c
    left JOIN [dbo].[BestKnowBy$] bkb
    ON c.[campaign_id] =bkb.Con_id
    where c.deleted = 0
)
SELECT cte.id, spl.value
FROM CTE_Query AS cte
CROSS APPLY string_split(cte.best_know_by, ',') spl

答案 1 :(得分:1)

Cross Apply可以解决问题

Select A.ID
      ,Names = B.Item   -- << Return Field from your Split Function
 From  YourTable A
 Cross Apply (Select * from dbo.Split(A.Names, ',') ) B
  

查询

SELECT c.[id]
      ,S.*      --<< Removed bkb.best_know_by and Replaced with S.* (don't know your Split() Return Field)
 FROM  [sugarcrm_cmsru_dev].[dbo].[contacts] c
 LEFT JOIN [dbo].[email_addr_bean_rel]  eb ON eb.[bean_id] = c.[id]
 JOIN [dbo].[email_addresses] ea ON ea.[id] = eb.[email_address_id]
 JOIN [dbo].[contacts_cstm] ccs   ON eb.bean_id = ccs.id_c
 LEFT JOIN [dbo].[BestKnowBy$] bkb   ON c.[campaign_id] =bkb.Con_id
 Cross Apply dbo.Split(bkb.best_know_by,',')  S
 where c.deleted = 0;