Question

我有一个输入：@dateInput。

例如：@dateInput = 2013/10/02（格式：yyyy / MM / dd）。

如何通过T-SQL

获得10月份的周（周一至周五）

StartWeek                  EndWeek
2013-10-01 00:00:00.000    2013-10-05 00:00:00.000
2013-10-07 00:00:00.000    2013-10-12 00:00:00.000
2013-10-14 00:00:00.000    2013-10-19 00:00:00.000
2013-10-21 00:00:00.000    2013-10-26 00:00:00.000
2013-10-28 00:00:00.000    2013-10-31 00:00:00.000

全部谢谢！

Answer 1

如果你大致知道一年中你可以生成一年和使用它们的配对

declare @input datetime
set @input = '20131002'

declare @monday datetime
set @monday='20121231'

declare @beginOfMonth datetime
declare @endOfMonth datetime

set @beginOfMonth = Substring(Convert(char,@input,102),1,8)+'01'
set @endOfMonth = DateAdd(month,1,@beginOfMonth)-1

declare @i int
set @i=1

create table #week
(StartDate datetime,
EndDate datetime)

while (@i <= 52)
begin
 insert into #week
 values (@monday, DateAdd(day,5,@monday))
 set @monday=DateAdd(week,1,@monday)
 set @i=@i+1
end

select * from #week
where StartDate between @beginOfMonth and @endOfMonth and EndDate between @beginOfMonth and    @endOfMonth 

drop table #week

T-SQL每月拆分一周

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