对于[0, 150]
列中的每个范围diff
,我想创建一个每次重置范围时增加1的组列。如果diff
为负数,则范围会重置。
import pandas as pd
df = pd.DataFrame({'year': [2016, 2016, 2016, 2016, 2016, 2016, 2016],
'month' : [1, 1, 2, 3, 3, 3, 3],
'day': [23, 25, 1, 1, 7, 20, 30]})
df = pd.to_datetime(df)
df = pd.concat([df, pd.Series(data=[15, 35, 80, 5, 20, 45, 90])], axis=1)
df.columns = ['date', 'percentworn']
col_shift = ['percentworn']
df_shift = df.shift(1).loc[:, col_shift]
df_combined = df.join(df_shift, how='inner', rsuffix='_2')
df_combined.fillna(value=0,inplace=True)
df_combined['diff'] = df_combined['percentworn'] - df_combined['percentworn_2']
grp
列应为0, 0, 0, 1, 1, 1, 1
。我试过的代码是
def grping(df):
df_ = df.copy(deep=True)
i = 0
if df_['diff'] >= 0:
df_['grp'] = i
else:
i += 1
df_['grp'] = i
return df_
df_combined.apply(grping,axis=1)
增量后我需要i += 1
持续存在。我怎样才能做到这一点?或者有更好的方法来获得理想的结果吗?
答案 0 :(得分:2)
IIUC你可以测试#post-34917 #attachment_34937 {
display: inline-block;
max-width: calc(100% - 220px);
position: relative;
margin-left: -20px;
}
#content .aligncenter>img {
width: 100%;
height: auto;
}
@media (max-width: 1023px) {
#post-34917 #attachment_34937 {
max-width: calc(100% - 170px);
}
}
列是否为负数,产生一个布尔数组,然后将其转换为'diff'
和调用int
:
cumsum
打破上述情况:
In [313]:
df_combined['group'] = (df_combined['diff'] < 0).astype(int).cumsum()
df_combined
Out[313]:
date percentworn percentworn_2 diff group
0 2016-01-23 15 0.0 15.0 0
1 2016-01-25 35 15.0 20.0 0
2 2016-02-01 80 35.0 45.0 0
3 2016-03-01 5 80.0 -75.0 1
4 2016-03-07 20 5.0 15.0 1
5 2016-03-20 45 20.0 25.0 1
6 2016-03-30 90 45.0 45.0 1