Question

我正在编写一个存储过程，我想检查范围内的可用数字。存储过程将返回0或1作为位。

案例0表示该号码不可用

案例1表示该号码可用。

我写了这个查询

Declare @recivedNo As INT = 82 
    Declare @minSourceNo as INT
    Declare @maxSourceNo as INT

    Select @minSourceNo =  min(Source_no) from Source 
    Select @maxSourceNo =  max(Source_no) from Source 

    IF(Select COunt(1) from Source
    WHere Source_no = @recivedNo AND @recivedNo Between @minSourceNo AND @maxSourceNo

    )>0
    begin 
    Select 0 as is_valid
    end
    else
    Select 1 as is_valid

假设最小数为1且最大值为88.可用数字为5。如果我检查数字10.它重新运行0这是正确的。如果我检查5号，则返回1，这很好。请注意，数字5和10都在该范围内。但如果我检查数字100.它也返回1，这对我来说是不正确的。它应该返回0，因为100不在范围内。有没有办法检查这个？

Answer 1

您在“表格中以及最小值和最大值之间”的评估不正确。您对该号码是否可用感兴趣（即“不在表格中以及在最小值和最大值之间”）。

select case when @recivedNo between @minSourceNo and @maxSourceNo 
            and not exists (select * from source where source_no = @recivedNo)
       then 1 else 0 end as is_valid;

反之亦然：

select case when @recivedNo not between @minSourceNo and @maxSourceNo 
            or exists (select * from source where source_no = @recivedNo)
       then 0 else 1 end as is_valid;

Answer 2

看起来你的if语句是个问题。试试＆＃34;如果存在＆＃34;如下

$_SERVER["HTTP_REFERER"]

如果存在，您也可以使用select * inside或从源

中选择top 1

IF EXISTS (Select count(1) from Source
WHere Source_no = @recivedNo AND (@recivedNo Between @minSourceNo AND @maxSourceNo)

)
BEGIN 
END
ELSE
BEGIN
END

Answer 3

您可以将@minSourceNo和@maxSourceNo放在一个查询中。在case语句中使用between：

DECLARE @recivedNo As INT = 10,
        @minSourceNo as INT,
        @maxSourceNo as INT

SELECT  @minSourceNo =  min(Source_no),
        @maxSourceNo =  max(Source_no) 
FROM @source

IF (
    SELECT COUNT(*)+CASE WHEN @recivedNo Between @minSourceNo AND @maxSourceNo THEN 1 ELSE 0 END
    FROM @source
    WHERE Source_no = @recivedNo 
) != 1 
SELECT 0 as is_valid
ELSE
SELECT 1 as is_valid

Answer 4

假设@minSourceNo，@ maxSourceNo可以有任意值

-- sample data - params
declare @Source table (sourceNo int);
insert @Source (sourceNo)
values (2),(25),(120);

Declare @minSourceNo as INT = 20;
Declare @maxSourceNo as INT = 50;

-- sample data
Declare @recivedSamples table (recivedNo int);
insert @recivedSamples(recivedNo)
values (2),(25),(30),(120);

-- query
select recivedNo, 
       flag=coalesce((select 1 n 
                 from @Source s
                 where s.sourceNo between @minSourceNo and @maxSourceNo
                  and s.sourceNo = r.recivedNo), 0)
from @recivedSamples r

Answer 5

由于您从@minSourceNo表本身获取变量@maxSourceNo和source的值，因此查询将从该表返回SourceNo的最小值和最大值。所以条件@recivedNo Between @minSourceNo AND @maxSourceNo将始终满足，除非并且直到@recivedNo表中没有输入Source。

无论如何，下面的脚本会做同样的事情，但使用EXIST。

    DECLARE @recivedNo    INT = 82 
    DECLARE @minSourceNo  INT
    DECLARE @maxSourceNo  INT

    SELECT  @minSourceNo =  min(Source_no), @maxSourceNo =  max(Source_no) FROM Source 


    IF EXISTS (SELECT 1 FROM Source
               WHERE Source_no = @recivedNo AND @recivedNo Between @minSourceNo AND @maxSourceNo)
        BEGIN 
        SELECT 1 AS is_valid
        END
    ELSE
        BEGIN
        SELECT 0 AS is_valid
        END

Answer 6

我写了这个查询，它运行正常。

Declare @number as INT = 120
Declare @minsourceNo as INT 
Declare @maxsourceNo as INT 

Select @minsourceNo =  min(source_no)  from source 
Select @maxsourceNo =  max(source_no)  from source 

IF EXists(Select * from source where source_no = @number)
Begin
select Cast(0 as bit)
end
else
If(@number between @minsourceNo and @maxsourceNo)
Begin
select Cast(1 as bit)
end
else
select Cast(0 as bit)

如何返回0或1来检查sql范围内的可用数字？

6 个答案: