Question

显示记分板的代码总是闪烁，因为我将背景设为白色。但我想要停下来。那么有没有办法让pygame完成所有这些绘图和填充而不更新显示，当绘图完成时它会显示新结果，所以我不必看到每一步，从而闪烁？

def score():
    while ScoreTrue:
        pygame.event.get()
        window.fill(white)
        display_score= (display_height/ 1.2)
        message_display("Scoreboard", 2, 5)
        message_meduim("5th place: " + ", ".join( repr(e) for e in Scoreboard[0] ), 3, display_score)
        message_meduim("4th place:" + ", ".join( repr(e) for e in Scoreboard[1]), 3, display_score - 100)
        message_meduim("3rd place:" + ", ".join( repr(e) for e in Scoreboard[2]), 3, display_score - 200)
        message_meduim("2nd place:" + ", ".join( repr(e) for e in Scoreboard[3]), 3, display_score - 300)
        message_meduim("1st place:" + ", ".join( repr(e) for e in Scoreboard[4]), 3, display_score - 400)
        Button("Play again", display_width/1.2,display_height/1.6, display_width/8, display_height/9, red, red_light, "play")

Answer 1

如果你有一个显示你的窗口的while循环（我假设你这样做），那么你可能在循环中调用pygame.display.flip()或pygame.display.update()。因此，您也不必在分数功能中调用pygame.display.update()。移除pygame.display.update()函数中的score，然后在while循环中调用score函数。

pygame闪烁屏幕修复

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