我希望当触摸开始时,播放器(红色圆圈)移动到圆形路径的另一侧。我已经让玩家遵循了一条道路,但我没有在互联网上找到我的问题的答案。
override func didMoveToView(view: SKView) {
player = SKSpriteNode(imageNamed: "circulo")
player.position = CGPoint(x: self.frame.width / 2, y: self.frame.height / 2 - 170)
player.color = colorGris
player.colorBlendFactor = 1
player.size = CGSize(width: 25, height: 25)
self.addChild(player)
player.zPosition = 3
}
override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
/* Called when a touch begins */
if gameStarted == false {
gameStarted = true
moveClockWise()
movingClockWise = true
}
}
func moveClockWise(){
let dx = player.position.x - self.frame.width / 2
let dy = player.position.y - self.frame.height / 2
let rad = atan2(dy, dx)
path = UIBezierPath(arcCenter: CGPoint(x:self.frame.width / 2, y: self.frame.height / 2) , radius: 170, startAngle: rad, endAngle: rad + CGFloat(M_PI * 4), clockwise: true)
let follow = SKAction.followPath(path.CGPath, asOffset: false, orientToPath: true, speed: 200)
player.runAction(SKAction.repeatActionForever(follow).reversedAction())
}
答案 0 :(得分:3)
在圆形路径中移动对象的最简单方法之一是
SKNode
容器x
位置设置为圆形路径的半径如果您想将精灵移动到另一侧或更改旋转的半径,只需
x
位置如果要更改旋转方向,
示例代码:
// 1) Create the container node
let node = SKNode()
// 2) Create a sprite
let sprite = SKSpriteNode(color:SKColor.blueColor(),size:CGSizeMake(20,20))
var rotation:CGFloat = CGFloat(M_PI)
let radius:CGFloat = 50
override func didMoveToView(view: SKView) {
scaleMode = .ResizeFill
node.position = view.center
// 3) Add the container to the scene
addChild(node)
// 4) Set the sprite's x position
sprite.position = CGPointMake(radius, 0)
// 5) Add the sprite to the container
node.addChild(sprite)
// 6) Rotate the container
rotate()
}
// Rotate the container
func rotate() {
let action = SKAction.rotateByAngle(rotation, duration: 4)
node.runAction(SKAction.repeatActionForever(action),withKey: "rotate")
}
// 8) Reverse the direction of the rotation
func reverse() {
rotation = -rotation
}
// Stop rotating the container
func stopRotation() {
if node.actionForKey("rotate") != nil {
node.removeActionForKey("rotate")
}
}
override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
/* 7) Change the sprite's x-position */
if sprite.actionForKey("move") == nil {
stopRotation()
let opposite = -sprite.position.x * 2
let move = SKAction.moveByX(opposite, y: 0, duration: 3)
let rotate = SKAction.runBlock {
self.rotate()
}
sprite.runAction(SKAction.sequence([move, rotate]), withKey: "move")
}
}
答案 1 :(得分:1)
我认为您可以按照以下步骤操作:
runAction
:你可以这样做:
let follow = SKAction.followPath(path.CGPath, asOffset: false, orientToPath: true, speed: 200)
player.runAction(SKAction.repeatActionForever(follow).reversedAction(),withKey:"followPath")
停止做简单:
player.removeActionForKey("followPath")
为此,我尝试使用您的代码使其易于理解:
var myCircle : CGMutablePath! = CGPathCreateMutable()
let newDx = player.position.x - self.frame.width / 2
let newDy = player.position.y - self.frame.height / 2
let newRad = atan2(newDy, newDx)
let newPath = UIBezierPath(arcCenter: CGPoint(x:self.frame.width / 2, y: self.frame.height / 2) , radius: 170, startAngle: newRad, endAngle: newRad + CGFloat(M_PI * 4), clockwise: true)
要做到这一点,你可以写:
var mirroring = CGAffineTransformMakeScale(1.0, -1.0) // flip horizontal
var mirrorPath : CGMutablePath! = CGPathCreateMutable()
CGPathAddPath(mirrorPath, &mirroring, newPath.CGPath)
runAction
:您可以在这里重新启动:
let newFollow = SKAction.followPath(mirrorPath, asOffset: false, orientToPath: true, speed: 200)
player.runAction(SKAction.repeatActionForever(newFollow).reversedAction(),withKey:"followPath")
<强>加成强>:
如果你可以添加一些漂亮的动画,例如点位置和圆圈中的镜像点之间的跳转,你需要知道CGPoint
目的地(在mirrorPath中它将是&#34; moveToPoint&#34 ;或者也是第一点)。 Here您可以找到获取所有CGPath
点的扩展程序,以便:
var mirrorPoints = mirrorPath.getPathElementsPoints()
let destinationPoint = mirrorPoints.first!
在Sprite-kit框架中,可用的SKAction's
之间还没有jumpAction,所以你可以用很少的代码创建它。
通常是&#34;跳跃&#34;通过更改Y坐标来制作,在您的情况下,您的视图是从高处开始,因此您可以进行缩放(缩放)。