当我在下面运行以下脚本时，我收到错误Too many input arguments（我已经发现在第二个intNH(5,2)循环中计算for时会发生这种情况）。基本上发生的事情是fun2 i=5等于0（因为相关的G元素是0）并且MATLAB不能在数值上积分等于零的函数（或者我就是这样解释的。）
有没有人对我如何克服这个问题有任何指示？我尝试了一些if语句，如果函数等于0然后intNH = 0，则其他数字正常整合，但是当我尝试这个时会发生更多错误！
%%Calculation of dH/dt for mode m=1 for the entire sphere, NH and SH
clear all
%%Radius of photosphere
R = 6.957*(10^5); %In km
%%Call in spherical harmonic coefficients, change the 535 figure as more
%%data is added to the spreadsheets
G(:,1) = xlsread('G Coefficients.xls', 'C3:C535');
G(:,2) = xlsread('G Coefficients.xls', 'E3:E535');
G(:,3) = xlsread('G Coefficients.xls', 'H3:H535');
G(:,4) = xlsread('G Coefficients.xls', 'L3:L535');
G(:,5) = xlsread('G Coefficients.xls', 'Q3:Q535');
G(:,6) = xlsread('G Coefficients.xls', 'W3:W535');
G(:,7) = xlsread('G Coefficients.xls', 'AD3:AD535');
G(:,8) = xlsread('G Coefficients.xls', 'AL3:AL535');
G(:,9) = xlsread('G Coefficients.xls', 'AU3:AU535');
%%Set function v which always remains the same
nhztoradperday = 2*pi*86400*(10^(-9));
a = 460.7*nhztoradperday;
b = -62.69*nhztoradperday;
c = -67.13*nhztoradperday;
syms t %t short for theta here
V = a + (b*cos(t)^2) + (c*cos(t)^4);
zero = @(t) 0*t;
%%Set B and A functions within separate matrices
for i = 1:length(G)
B(i,1) = G(i,1)*cos(t);
B(i,2) = 0.5*G(i,2)*(3*(cos(t)^2)-1);
B(i,3) = 0.5*G(i,3)*(5*(cos(t)^3)-3*cos(t));
B(i,4) = 1/8*G(i,4)*(35*(cos(t)^4)-30*(cos(t)^2)+3);
B(i,5) = 1/8*G(i,5)*(63*(cos(t)^5)-70*(cos(t)^3)+15*cos(t));
B(i,6) = 1/16*G(i,6)*(231*(cos(t)^6)-315*(cos(t)^4)+105*(cos(t)^2)-5);
B(i,7) = 1/16*G(i,7)*(429*(cos(t)^7)-693*(cos(t)^5)+315*(cos(t)^3)-35*cos(t));
B(i,8) = 1/128*G(i,8)*(6435*(cos(t)^8)-12012*(cos(t)^6)+6930*(cos(t)^4)-1260*(cos(t)^2)+35);
B(i,9) = 1/128*G(i,9)*(12155*(cos(t)^9)-25740*(cos(t)^7)+18018*(cos(t)^5)-4620*(cos(t)^3)+315*cos(t));
A(i,1) = 0.5*R*G(i,1)*sin(t);
A(i,2) = 0.5*R*G(i,2)*csc(t)*(cos(t)-(cos(t)^3));
A(i,3) = 0.5*R*G(i,3)*csc(t)*(1.5*(cos(t)^2)-1.25*(cos(t)^4)-0.25);
A(i,4) = 1/8*R*G(i,4)*csc(t)*(-7*(cos(t)^5)+10*(cos(t)^3)-3*cos(t));
A(i,5) = 1/8*R*G(i,5)*csc(t)*(-21/2*(cos(t)^6)+35/2*(cos(t)^4)-15/2*(cos(t)^2)+0.5);
A(i,6) = 1/16*R*G(i,6)*csc(t)*(-33*(cos(t)^7)+63*(cos(t)^5)-35*(cos(t)^3)+5*cos(t));
A(i,7) = 1/16*R*G(i,7)*csc(t)*(-429/8*(cos(t)^8)+231/2*(cos(t)^6)-315/4*(cos(t)^4)+35/2*(cos(t)^2)-5/8);
A(i,8) = 1/128*R*G(i,8)*csc(t)*(-715*(cos(t)^9)+1716*(cos(t)^7)-1386*(cos(t)^5)+420*(cos(t)^3)-35*cos(t));
A(i,9) = 1/128*R*G(i,9)*csc(t)*(-2431/2*(cos(t)^10)+6435/2*(cos(t)^8)-3003*(cos(t)^6)+1155*(cos(t)^4)-315/2*(cos(t)^2)+7/2);
end
%Turn vector V from a sym to a function and compute V at equator
Vfunc = matlabFunction(V);
Veq = Vfunc(0);
for i=1:length(G)
fun(1) = 0; fun(2) = 0; fun(3) = 0; fun(4) = 0; fun(5) = 0; fun(6) = 0;
fun(7) = 0; fun(8) = 0; fun(9) = 0;
%Create functions for integration
fun(1) = matlabFunction(B(i,1).*A(i,1).*(V-Veq).*sin(t));
fun(2) = matlabFunction(B(i,2).*A(i,2).*(V-Veq).*sin(t));
fun(3) = matlabFunction(B(i,3).*A(i,3).*(V-Veq).*sin(t));
fun(4) = matlabFunction(B(i,4).*A(i,4).*(V-Veq).*sin(t));
fun(5) = matlabFunction(B(i,5).*A(i,5).*(V-Veq).*sin(t));
fun(6) = matlabFunction(B(i,6).*A(i,6).*(V-Veq).*sin(t));
fun(7) = matlabFunction(B(i,7).*A(i,7).*(V-Veq).*sin(t));
fun(8) = matlabFunction(B(i,8).*A(i,8).*(V-Veq).*sin(t));
fun(9) = matlabFunction(B(i,9).*A(i,9).*(V-Veq).*sin(t));
%Compute numerical integral for each order and store values
%Northern Hemisphere
intNH(i,1) = integral(fun1,0,pi/2);
intNH(i,2) = integral(fun2,0,pi/2);
intNH(i,3) = integral(fun3,0,pi/2);
intNH(i,4) = integral(fun4,0,pi/2);
intNH(i,5) = integral(fun5,0,pi/2);
intNH(i,6) = integral(fun6,0,pi/2);
intNH(i,7) = integral(fun7,0,pi/2);
intNH(i,8) = integral(fun8,0,pi/2);
intNH(i,9) = integral(fun9,0,pi/2);
%Southern Hemisphere
intSH(i,1) = int(fun1,t,pi/2,pi);
intSH(i,2) = int(fun2,t,pi/2,pi);
intSH(i,3) = int(fun3,t,pi/2,pi);
intSH(i,4) = int(fun4,t,pi/2,pi);
intSH(i,5) = int(fun5,t,pi/2,pi);
intSH(i,6) = int(fun6,t,pi/2,pi);
intSH(i,7) = int(fun7,t,pi/2,pi);
intSH(i,8) = int(fun8,t,pi/2,pi);
intSH(i,9) = int(fun9,t,pi/2,pi);
%Whole Sun
intSun(i,1) = int(fun1,t,0,pi);
intSun(i,2) = int(fun2,t,0,pi);
intSun(i,3) = int(fun3,t,0,pi);
intSun(i,4) = int(fun4,t,0,pi);
intSun(i,5) = int(fun5,t,0,pi);
intSun(i,6) = int(fun6,t,0,pi);
intSun(i,7) = int(fun7,t,0,pi);
intSun(i,8) = int(fun8,t,0,pi);
intSun(i,9) = int(fun9,t,0,pi);
%Sum over all orders to get a value for dH/dt
NH(i) = sum(dintNH(i,:));
SH(i) = sum(intSH(i,:));
Sun(i) = sum(intSun(i,:));
end
x = linspace(1643,2175,533);
figure(1)
plot(x,NH)
xlabel('Carrington Rotation')
ylabel('Magnetic helicity transport')
title('Northern Hemisphere magnetic helicity transport via twisting motions on the boundary vs Carrington Rotations')
figure(2)
plot(x,SH)
xlabel('Carrington Rotation')
ylabel('Magnetic helicity transport')
title('Southern Hemisphere magnetic helicity transport via twisting motions on the boundary vs Carrington Rotations')
figure(3)
plot(x,Sun)
xlabel('Carrington Rotation')
ylabel('Magnetic helicity transport')
title('Whole sun magnetic helicity transport via twisting motions on the boundary vs Carrington Rotations')
答案 0 :(得分：3)
您的代码存在许多问题。所有这些魔法你用syms和手动设置函数值数组是完全没必要的，而且很难分辨确切的问题来自哪里（如果你把这段代码放到一个函数中，至少我们知道这行错误来自......）。
您应该使用匿名函数，就像代码中名为zero的函数一样。您拥有的只是分析定义的函数和数字。您只能在cell个对象中存储函数（句柄），而不能存储在数组中。因此，fun{k}和朋友应该为此分配。但是如果你重写代码来处理数值（这实际上也是MATLAB的最佳选择），你最终会变得更快乐。
例如，您的第一个循环等同于：
B{1} = @(t) G(:,1)*cos(t);
B{2} = @(t) 0.5*G(:,2)*(3*(cos(t)^2)-1);
B{3} = @(t) 0.5*G(:,3)*(5*(cos(t)^3)-3*cos(t));
B{4} = @(t) 1/8*G(:,4)*(35*(cos(t)^4)-30*(cos(t)^2)+3);
B{5} = @(t) 1/8*G(:,5)*(63*(cos(t)^5)-70*(cos(t)^3)+15*cos(t));
B{6} = @(t) 1/16*G(:,6)*(231*(cos(t)^6)-315*(cos(t)^4)+105*(cos(t)^2)-5);
B{7} = @(t) 1/16*G(:,7)*(429*(cos(t)^7)-693*(cos(t)^5)+315*(cos(t)^3)-35*cos(t));
B{8} = @(t) 1/128*G(:,8)*(6435*(cos(t)^8)-12012*(cos(t)^6)+6930*(cos(t)^4)-1260*(cos(t)^2)+35);
B{9} = @(t) 1/128*G(:,9)*(12155*(cos(t)^9)-25740*(cos(t)^7)+18018*(cos(t)^5)-4620*(cos(t)^3)+315*cos(t));
A{1} = @(t) 0.5*R*G(:,1)*sin(t);
A{2} = @(t) 0.5*R*G(:,2)*csc(t)*(cos(t)-(cos(t)^3));
A{3} = @(t) 0.5*R*G(:,3)*csc(t)*(1.5*(cos(t)^2)-1.25*(cos(t)^4)-0.25);
A{4} = @(t) 1/8*R*G(:,4)*csc(t)*(-7*(cos(t)^5)+10*(cos(t)^3)-3*cos(t));
A{5} = @(t) 1/8*R*G(:,5)*csc(t)*(-21/2*(cos(t)^6)+35/2*(cos(t)^4)-15/2*(cos(t)^2)+0.5);
A{6} = @(t) 1/16*R*G(:,6)*csc(t)*(-33*(cos(t)^7)+63*(cos(t)^5)-35*(cos(t)^3)+5*cos(t));
A{7} = @(t) 1/16*R*G(:,7)*csc(t)*(-429/8*(cos(t)^8)+231/2*(cos(t)^6)-315/4*(cos(t)^4)+35/2*(cos(t)^2)-5/8);
A{8} = @(t) 1/128*R*G(:,8)*csc(t)*(-715*(cos(t)^9)+1716*(cos(t)^7)-1386*(cos(t)^5)+420*(cos(t)^3)-35*cos(t));
A{9} = @(t) 1/128*R*G(:,9)*csc(t)*(-2431/2*(cos(t)^10)+6435/2*(cos(t)^8)-3003*(cos(t)^6)+1155*(cos(t)^4)-315/2*(cos(t)^2)+7/2);
这些都是包含数组值函数句柄的单元格。这些函数中的每一个都获得单个值t并输出一个长度为length(G)的数组。
稍后，您可以
V = @(t) a + (b*cos(t)^2) + (c*cos(t)^4);
Veq = V(0);
% todo: pre-allocate fun
intNH = zeros(length(G),9);
for k=1:9
fun{k} = @(t) B{k}(t).*A{k}(t).*(V(t)-Veq).*sin(t);
intNH(:,k) = integral(fun{k},0,pi/2,'arrayvalued',true);
end
等等。