我制作的游戏目标是收集最大数量的球（矩形）以获得最高分。球从智能手机的每一侧中间随机产生，你使用屏幕中间的方块（每次触摸屏幕时方块向右旋转90度）得到球。正方形（矩形）有三个黑色边和一个黄色边。
我想在这里完成的是如果一个球击中方块的黄色边，你得到一分，但如果一个球撞到了方形的黑色边，你将输掉比赛。 / p>
这是我到目前为止所拥有的（已经有碰撞，旋转和球产生）：
@Override
public void create(){
batch = new SpriteBatch();
Ball = new Texture("energyball.png");
Up = new Texture("up.png");
upSprite = new Sprite(Up);
upSprite.setOriginCenter();
upSprite.setX(615);
upSprite.setY(340);
upSprite.setRegionWidth(64);
upSprite.setRegionHeight(64);
square = new Rectangle();
square.set(630, 360, 32, 32);
cam = new OrthographicCamera();
cam.setToOrtho(false, 1280, 720);
upSprite.setPosition(upSprite.getX(), upSprite.getY());
// calls the functions to spawn balls randomly
balls1 = new Array<Rectangle>();
spawnBalls1();
balls2 = new Array<Rectangle>();
spawnBalls2();
balls3 = new Array<Rectangle>();
spawnBalls3();
balls4 = new Array<Rectangle>();
spawnBalls4();
score();
//if the screen is touched sprite rotates 90 degrees clockwise
Gdx.input.setInputProcessor(new InputAdapter() {
@Override
public boolean touchDown(int x, int y, int pointer, int button) {
return true;
}
@Override
public boolean touchUp(int x, int y, int pointer, int button) {
upSprite.rotate(-90);
return true;
}
});
}
//shows score
private void score() {
score = 0;
showScore = "Score: 0";
scoreFont = new BitmapFont();
}
//creates the balls and sets their position as well as the random timer for each
private void spawnBalls1() {
ball1.x = MathUtils.random(639, 641);
ball1.y = 720;
ball1.width = 32;
ball1.height = 32;
balls1.add(ball1);
lastDropTime = TimeUtils.nanoTime();
}
private void spawnBalls2() {
ball2.x = 0;
ball2.y = MathUtils.random(359, 361);
ball2.width = 32;
ball2.height = 32;
balls2.add(ball2);
lastDropTime = TimeUtils.nanoTime();
}
private void spawnBalls3() {
ball3.x = MathUtils.random(639, 641);
ball3.y = 0;
ball3.width = 32;
ball3.height = 32;
balls3.add(ball3);
lastDropTime = TimeUtils.nanoTime();
}
private void spawnBalls4() {
ball4.x = 1280;
ball4.y = MathUtils.random(359, 361);
ball4.width = 32;
ball4.height = 32;
balls4.add(ball4);
lastDropTime = TimeUtils.nanoTime();
}
@Override
public void render() {
Gdx.gl.glClearColor(0, 0, 0, 1);
Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);
cam.update();
//draws the game itself as well as the balls on the screen
batch.setProjectionMatrix(cam.combined);
batch.begin();
upSprite.draw(batch);
//draws the balls
for (Rectangle ball1 : balls1) {
batch.draw(Ball, ball1.x, ball1.y);
}
for (Rectangle ball2 : balls2) {
batch.draw(Ball, ball2.x, ball2.y);
}
for (Rectangle ball3 : balls3) {
batch.draw(Ball, ball3.x, ball3.y);
}
for (Rectangle ball4 : balls4) {
batch.draw(Ball, ball4.x, ball4.y);
}
scoreFont.setColor(1, 1, 1, 1);
scoreFont.draw(batch, showScore, 25, 100);
batch.end();
// if the time minus the time of the last ball spawn is less than x then spawn another ball in a random place
if (TimeUtils.nanoTime() - lastDropTime > 1000000000) {
switch (MathUtils.random(4)) {
case 0:
spawnBalls1();
break;
case 1:
spawnBalls2();
break;
case 2:
spawnBalls3();
break;
case 3:
spawnBalls4();
break;
}
}
Iterator<Rectangle> iter1 = balls1.iterator();
while(iter1.hasNext()) {
Rectangle balls1 = iter1.next();
balls1.y -= 350 * Gdx.graphics.getDeltaTime();
if (balls1.overlaps(square)) {
score++;
showScore = "Score: " + score;
iter1.remove();
}
}
Iterator<Rectangle> iter2 = balls2.iterator();
while (iter2.hasNext()) {
Rectangle balls2 = iter2.next();
balls2.x += 550 * Gdx.graphics.getDeltaTime();
if (balls2.overlaps(square)) {
score++;
showScore = "Score: " + score;
iter2.remove();
}
}
Iterator<Rectangle> iter3 = balls3.iterator();
while(iter3.hasNext()) {
Rectangle balls3 = iter3.next();
balls3.y += 350 * Gdx.graphics.getDeltaTime();
if (balls3.overlaps(square)) {
score++;
showScore = "Score: " + score;
iter3.remove();
}
}
Iterator<Rectangle> iter4 = balls4.iterator();
while(iter4.hasNext()) {
Rectangle balls4 = iter4.next();
balls4.x -= 550 * Gdx.graphics.getDeltaTime();
if (balls4.overlaps(square)) {
score++;
showScore = "Score: " + score;
iter4.remove();
}
}
}
如果有人能帮助我，真的很高兴。谢谢！
答案 0 :(得分：0)
我现在无法正确编写代码，但您可以使用此逻辑，
我希望，我理解你的需要并且可以提供帮助。
答案 1 :(得分：0)
我无法让你成为一个例子，但我希望你能用这种方法解决问题。
public static boolean intersectRaySphere (Ray ray, Vector3 center, float radius, Vector3 intersection) {
final float len = ray.direction.dot(center.x - ray.origin.x, center.y - ray.origin.y, center.z - ray.origin.z);
if (len < 0.f) // behind the ray
return false;
final float dst2 = center.dst2(ray.origin.x + ray.direction.x * len, ray.origin.y + ray.direction.y * len,
ray.origin.z + ray.direction.z * len);
final float r2 = radius * radius;
if (dst2 > r2)
return false;
if (intersection != null)
intersection.set(ray.direction).scl(len - (float)Math.sqrt(r2 - dst2)).add(ray.origin);
return true;
}