Question

我有一系列我希望绘制的点，但如果点相距太远，则可能会在结果曲线处断开。

所以在1D CASE中：

1 2 3 7 9 11 12  16 18 19

就像：

         1-2-3  7-9-11-12  16-18-19

or :      seq1     seq2      seq3

我想将我的序列绘制为未连接的离散部分seq1 seq2和seq3。

我不太清楚如何去做这个

Answer 1

将下面的代码段添加到您的问题解决方案中。我尽可能在代码中解释，但如果有什么不清楚，请不要犹豫。

% constants, thresold defintion
T = 4;
% your data
a = [1 2 3 7 9 11 12 16 18 19 24 25 26 28 35 37 38 39];

% preparing the x-axis
x = 1:length(a);

% Getting the differences between the values
d = diff(a);
% find the suggested "jumps/gaps", greater/equal than the threshold
ind = find(d>=T);

figure;
hold on;
% Plotting the first part of a
y = nan*ones(1,length(a));
y(1:ind(1)) = a(1:ind(1));
plot(x,y);

% Plotting all parts in between: go through all found gaps
% and plot the corresponding values of "a" between them
for j=2:length(ind)
    y = nan*ones(1,length(a));
    y(ind(j-1)+1:ind(j)) = a(ind(j-1)+1:ind(j));
    plot(x,y);
end;

% Plotting the last part of a
y = nan*ones(1,length(a));
y(ind(j)+1:end) = a(ind(j)+1:end);
plot(x,y);

绘制曲线作为较小的部分，matlab

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